Answer:
Im definitely sure that this is the answer A) 1.8 < 6 < 1.9
Answer:
Developed Length
Step-by-step explanation:
A developed length is the length along the centre line of a circular shape.
From the question, the degree of bend is 90°
Also, from the question; the length of an arc of 1 quadrant.
1 quadrant = 90°
And the degree of bend = 90° (from the question)
So, it's safe to say 1 quadrant = the degree of bend = 90°
A small change in 90° will move change the quadrant to another quadrant.
So, at exactly 90° (or other multiples of 90° which are 180°, 270° and 360°), it is at its developed length.
Hi, Siyasi2 ! Let x = the number of hot dogs, y = the number of chips, and z = the number of drinks. Then we know:
5x + 4y + 5z = 15.75
x = y + 0.75
z = 2x - 1
Let's substitute the 3rd equation into the first one.
5x + 4y + 5(2x - 1) = 15.75
5x + 4y+ 10x - 5 = 15.75
15x + 4y = 20.75
Now, let's re-write the 2nd equation as x - y = 0.75
We now have a system of two equations with two unknowns.
15x + 4y = 20.75
x - y = 0.75
To solve this, we can multiply the bottom equation by 4 and add.
15x + 4y = 20.75
+ 4(x - y = 0.75)
19x = 23.75
or x = 1.25
If x = 1.25, then using the one of the equations above, we can solve for y.
x - y = 1.25 - y = 0.75
.50 = y
Since z = 2x - 1, then z = 2(1.25) - 1 = 2.5 - 1 = 1.50
So, a hot dog is $1.25, chips are 50 cents, and a soft drink is $1.50. Please let me know if you have any questions.
Answer:
y + 3 = (6)(x - 6)
Step-by-step explanation:
The proper format for this equation y-1/6x+9 is y = (-1/6)x+9.
Any line perpendicular to y = (-1/6)x+9 has the slope which is the negative reciprocal of that of y = (-1/6)x+9, or the negative reciprocal of -1/6. That is +6.
Thus, the desired line, which passes through (6, -3), is found using the point-slope formula for the equation of a straight line:
y + 3 = (6)(x - 6)
Answer: The area of the path=
Step-by-step explanation:
Given: The side length of square garden included the path= 10 ft
Then the area of the field which included both gardens and path= 
The width of the path = 1 ft
Therefore, the side of square vegetable garden = 10-2=8 ft
The area of vegetable garden =
Therefore, the area of the path=