2 * plane speed in still air = 289mph + 257mph = 546
plane speed in still air = 273 mph
plane speed in still air + wind speed = 289
273 + wind speed = 289
Therefore, wind speed = 16 mph
Answer:
3
Step-by-step explanation:
x = 2
y = 0
plug in values
- 0(2-0)-1
4- 0(2)-1
4-0-1
4-1
3
Answer: 81
Step-by-step explanation:
(3^2)^2=81
Hope that helped
A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
__
a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
__
c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
The question gives the relationship to be
We will interpolate to solve the question.
First Question: 147 mi
Cross multiplying,
