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UkoKoshka [18]
3 years ago
12

Jeff rents a truck. the truck rental place charges$38 per day plus $0.25 per mile to rent the truck. how many miles can Jeff tra

vel in one day for $200?
Mathematics
2 answers:
Bingel [31]3 years ago
6 0
38+0.25x=200
-38. -38
0.25x=162
Divide by 0.25
X= 648
jolli1 [7]3 years ago
3 0
Im pretty sure he can travel 800 miles not counting the truck rental fee. Im not 100% sure though.

Hope this helps!
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Mark has $100,000 to invest. His financial consultant advises him to diversify his investment in three types of bonds: short-ter
galina1969 [7]

Answer:

Short-Term investment: 5000$

Intermediate-Term investment: 65000$

Long-Term investment: 30000$

Step-by-step explanation:

To construct our first equation lets define sort-term bond investment as x, long-term investment as y.

So the equation is:

x*0,04+(100000-x-y)*0,05+y*0,06=5250

From the equation it is found that:

y=25000+x

Instead of y, if we put 25000+x the equation will be as following:

x*0,04+75000*0,05+(25000+x)*0,06=5250

From the equation it is found that:

x=5000

Short-Term investment is 5000$

x+25000=y

Long-Term investment is 30000$

Rest of the money is Intermediate-Term investment 65000$

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3 years ago
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shtirl [24]
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3 0
3 years ago
Read 2 more answers
What would F^-1(-2) equal
Reil [10]

Answer:

I hope this helps:)

Step-by-step explanation:

4 0
3 years ago
And the number 6,497.4, the four next to the six is worth ___ times the other four.
FrozenT [24]
Yeah the answer is c
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The distribution of a sample of the outside diameters of PVC pipes approximates a normal distribution. The mean is 14.0 inches,
lakkis [162]

Answer:

A. 13.9 and 14.1 inches

See explanation below.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the outside diameters of a population, and for this case we know the distribution for X is given by:

X \sim N(14,0.1)  

Where \mu=14 and \sigma=0.1

If we want the middle 68% of the data we need to have on the tails 16% on each one

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.84   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.16 of the area on the left and 0.84 of the area on the right it's z=-0.994. On this case P(Z<-0.994)=0.16 and P(z>-0.994)=0.84

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.994

And if we solve for a we got

a=14 -0.994*0.1=13.9

And since the distribution is symmetrical for the upper limit we can use z = 0.994 and we have:

z=0.994

And if we solve for a we got

a=14 +0.994*0.1=14.1

So the correct answer for this case would be:

A. 13.9 and 14.1 inches

3 0
3 years ago
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