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Vlad [161]
2 years ago
12

Which value, when placed in the box, would result in a system of equations with infinitely many solutions? y = -2x 4 6x 3y =

Mathematics
1 answer:
wariber [46]2 years ago
8 0

The missing value is 12 in a system of equations with infinitely many solutions conditions.

It is given that in the system of equations there are two equations given:

\rm y =n -2x+4\\\rm and \\\rm 6x+3y= ?

It is required to find the missing value in the second equation.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.

We have equations:

\rm y = -2x+4 ....(1)\\  \\\rm 6x+3y= ?  ....(2)

Let's suppose the missing value is 'Z'

We know that the two pairs of equations have infinitely many solutions if and if they have the same coefficients of variables and the same constant on both sides.

From equation (1)

\rm y = -2x+4 \\\\\rm 2x+y=4(multiply both the sides by 3)

\rm 6x+3y=12 ...(3)

By comparing the equation (2) and (3), we get

M = 12

Thus, the missing value is 12 in a system of equations with infinitely many solutions conditions.

Learn more about the linear equation.

brainly.com/question/11897796

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X^2+2x+1 is a perfect square trinomial <br><br> True of False?
Nimfa-mama [501]

Answer:

True.

Step-by-step explanation:

It is because it is in the form a^2x^2+2abx+b^2 and this equals (ax+b)^2.

Why it is in that form:  well comparing  a^2x^2+2abx+b^2, we have a=1, b=1. Testing, plug in those values:

(1)^2x^2+2(1)(1)x+(1)^2

1x^2+2x+1

x^2+2x+1.

This has the squared form of (x+1)^2.

Test if you like:

(x+1)^2

(x+1)(x+1)

Use foil to expand:

First: x(x)=x^2

Outer: x(1)=x

Inner: 1(x)=x

Last: 1(1)=1

---------------Add together

x^2+2x+1

It does indeed equal.

4 0
2 years ago
Find the modulus of -2 - 6i.<br><br> 40<br> -40<br> 6.3<br> -6.3
olga2289 [7]
The modulus of complex number can be computed with this equation:
|z|=sqrt(Re(z)^2+Im(z)^2)
z = -2-6i
Re(z)=-2, so Re(z)^2=4
Im(z)=-6, so Im(z)^2=36
|z|=sqrt(36+4)=sqrt(40)=6.3
6 0
3 years ago
Problem 1:
wariber [46]

Answer:

x=1/6

Step-by-step explanation:

3x+4=9x+3

isolate x

1=6x

1/6=x

6 0
2 years ago
Read 2 more answers
Have any idea on this question ?
rewona [7]
The answer is D just trust me 
8 0
3 years ago
If ΔLMN ≅ ΔOPR, m∠L = (x^2 - x)°, m∠P = 16°, m∠N = (4x+160)°. Find m∠R.
Marizza181 [45]

Answer:

mZR = (4x + 160)°

Step-by-step explanation:

cause, mZR = mZN

;-))

8 0
2 years ago
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