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4 years ago

Which of the following symbols could correctly finish the statement? select all that apply.

Mathematics

2 answers:

fenix001 [56]4 years ago

7 0

Answer:

A and B

Step-by-step explanation:

Artemon [7]4 years ago

4 0

Answer:

Part A) the answer is =

Part B) the answer is >

Step-by-step explanation:

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What is the product of the fraction below? 5/2•3/10

Citrus2011 [14]

Answer:

3/4 is your answer.

Step-by-step explanation:

What you do is you times the fractions together.

3/4 is your answer.

5 0

3 years ago

Read 2 more answers

The equation for x: 3(x - 4) = 3x + 2 *

mash [69]

Answer:

No Solution

Step-by-step explanation:

For the left side of the equation, we can use distributive property

3(x-4)= 3x+2

3x-12=3x+2

+12 +12

3x= 3x+14

-3x -3x

0 is not equal to 14

No Solution

5 0

3 years ago

There are 115 students in a music club 73 of them are girls what is the ratio of the number of boys and girls

REY [17]

Answer:

73:42

Step-by-step explanation:

1115-73=42

G : B

73 : 42

8 0

3 years ago

Eduardo has 24$ saved . if he saves 8$ each week how much money will he in 5 weeks .

lyudmila [28]

Answer:

is you are not adding in the 24 then 40 if you are adding in the 24 then 64

Step-by-step explanation:

8 0

3 years ago

I forgot how to do this.... can somebody help?

slamgirl [31]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}

$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template in mind, let's see

3 units to the right, that means C/B = -3 so hmm C = -3 and B = 1 will do, -3/1 = -3

vertical stretch by 2, so A = 2
reflected over the x-axis, so that means is flipped upside-down, so A = -2 then

and shifted down by 3, do D = -3

$\bf f(x)={{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}\implies f(x)={{ -2}}(\mathbb{R})^{{{ 1}}x-{{ 3}}}-{{3}}\\\\\\ f(x)={{ -2}}(3)^{{{ }}x-{{ 3}}}-{{3}}$

3 0

4 years ago