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3 years ago

15 POINTS!!! ANSWER THESE 2 QUESTIONS

Mathematics

2 answers:

mote1985 [20]3 years ago

8 0

I hope it can help you hehe

iris [78.8K]3 years ago

6 0

#1 by borrowing from the other number #2 after you borrowed the 5 was supposed to be a 4 so 4-2=2 but you put 3 so your answer should be 2,473.

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What is equivalent to (73)–2

mario62 [17]

Answer:

Step-by-step explanation:

(73)-2 is equivalent to 71

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2 years ago

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The volume of air inside a rubber ball with radius r can be found using the function V(r) = four-thirds pi r cubed. What does V

Nat2105 [25]

Corrected Question

The volume of air inside a rubber ball with radius r can be found using the function V(r) = four-thirds pi r cubed. What does V(5/7) represent?

Answer:

(B)the volume of the rubber ball when the radius equals five-sevenths feet

Step-by-step explanation:

The Volume of a sphere of radius r can be found using the formula:

$V(r)=\dfrac43 \pi r^3$

Therefore comparing the expression: $V(\dfrac57)$ with V(r):

$Radius, r=\dfrac57$

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The correct option is B.

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3 years ago

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A recipe calls for 2/3 of a cup of milk. Zeinab wants to make 1/4 of the original recipe. How many cups of milk does Zeinab need

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Answer:

1/6 of a cup of milk. Or at least that's my answer.

Step-by-step explanation:

Okay, we need to find out 25% of 2/3.

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3 years ago

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

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3 years ago

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Luden [163]

Answer:

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20. 196

22. $\frac{256}{25}$

23. $\frac{1}{16}$

24. $\frac{2}{9}$

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3 years ago