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2 years ago

Write the equation of the line that is parallel to

Mathematics

2 answers:

baherus [9]2 years ago

8 0

Answer:

y = - x + 2

Step-by-step explanation:

We can use the below formula to find the equation of a line.

y = m x + c

Here,

m ⇒ slope

c ⇒ y - intercept

We know that , if two lines are parallel to each other, it means that the slopes of two lines are also equal.

Therefore, according to the question we have to find the y - intercept in order to write the equation of the line.

For that, you can use the given coordinate of the new line.

<em>Also, as the two lines are parallel, the slope of the new line is (-1 ).</em>

Let us solve now.

( -6 , 8 ) ⇒ ( x , y )

y = m x + c

8 = -1 × -6 + c

8 = 6 + c

8 - 6 = c

2 = c

And now let us write the equation of the line.

y = m x + c

y = - x + 2

Hope this helps you :-)

Let me know if you have any other questions :-)

Kruka [31]2 years ago

4 0

Answer:

y = -x + 2

Step-by-step explanation:

Lines that are parallel have the same slope but different

y-intercepts.

So the slope of the parallel line is -x

We can input the x and y points given to solve for the new y-intercept

y = -x + b
8 = -(-6) + b
8 = 6 + b
b = 2

The new line is y = -x + 2. Since these two lines are the same, they are coinciding lines.

-Chetan K

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Step-by-step explanation:

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3 years ago

Let (-7, 2) be a point on the terminal side of 0.

nekit [7.7K]

By applying the definitions of <em>trigonometric</em> functions, the <em>exact</em> values of the sine, secant and tangent of the point on the <em>terminal</em> side are $\sin \theta = \frac{2}{\sqrt{53}}$ , $\sec \theta = -\frac{\sqrt{53}}{7}$ and $\tan \theta = -\frac{2}{7}$ .

<h3>How to determine the exact values</h3>

In this question we need to find the exact values of three <em>trigonometric</em> functions associated with the <em>terminal</em> side of an angle. The following definitions are used:

Sine

$\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}$ (1)

Secant

$\sec \theta = \frac{\sqrt{x^{2}+y^{2}}}{x}$ (2)

Tangent

$\tan \theta = \frac{y}{x}$ (3)

If we know that x = - 7 and y = 2, then the exact values of the three <em>trigonometric</em> functions:

Sine

$\sin \theta = \frac{2}{\sqrt{53}}$

Secant

$\sec \theta = -\frac{\sqrt{53}}{7}$

Tangent

$\tan \theta = -\frac{2}{7}$

<h3>Remark</h3>

The statement reports typing errors, correct form is shown below:

<em>Let (x, y) = (- 7, 2) be a point on the terminal side of θ. Find the exact value of sin θ, sec θ and tan θ.</em>

To learn more on trigonometric functions: brainly.com/question/6904750

#SPJ1

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1 year ago