Answer/Step-by-step explanation:
1. The vertex of am angle is formed when two lines join together. The vertex of the angle shown in the diagram is located outside the circle.(<R)
2. The lines that created <FRT (lines FR & TR) are secants
3. The major arc = FT = 140°
minor arc = QS = 44°
4. Formula of Exterior angles of a circle = (major arc - minor arc)/2
x = (140 - 44)/2
x = 96/2
x = 48°
The geometrical relationships between the straight lines AB and CD is that they are parallel to each other
<h3>How to determine the relationship</h3>
It is important to note the following;
- A drawn from the origin and passes through point A (a , b), then the equation of OA = ax + by
- If a line is drawn from the origin and passes through point B (c , d), then the equation of OB = cx + dy
We find the equation of AB by subtracting OB from OA, thus AB = (c - a)x + (d - b)y
The slope of line AB =
⇒ OA= 2 x + 9 y
⇒ OA = 4 x + 8 y
⇒AB = OB - OA
⇒AB = (4 x + 8 y) - (2 x + 9 y)
⇒ AB = 4 x + 8 y - 2 x - 9 y
Collect like terms
⇒ AB = (4 x - 2 x) + (8 y - 9 y)
⇒AB = 2 x + -y
⇒ AB = 2 x - y
⇒ Coefficient of x = 2
⇒ Coefficient of y = -1
⇒ The slope of ab =
= 2
For CD
⇒ CD = 4 x - 2 y
⇒Coefficient of x = -4
⇒ Coefficient of y = -2
⇒The slope of cd =
= 2
Note that Parallel lines have same slopes
And Slope of ab = slope of cd
AB // CD
Therefore, the geometrical relationships between the straight lines AB and CD is that they are parallel to each other
Learn more about parallel lines here:
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Answer:Well All i know is that the answer is not C I'm sorry I dont know the correct answer but I know for a fact that the answer isn't C
Step-by-step explanation:
Short answer: you don't.
The linear term in the numerator of the integral means the form shown is not applicable. Rather, you perform the integration using partial fraction expansion.

The integral is ...
... (1/35)ln|5x-1| +(6/35)ln|5x+13| +C
_____
If the numerator of your integral were a constant, then the fractions multiplying the separate partial fraction integrals would have the same magnitude and opposite signs. You would end with the difference of logarithms, which could be expressed as the log of a ratio as shown in your problem statement.