Circumference of the outer circle = 2πr = 2π(6) = 12π
circumference of the outer arc = 120/360 x 12π = 12.57cm
circumference of the inner circle = 2πr = 2π(5) = 10π
circumference of the inner arc = 120/360 x 10π = 10.47 cm
Difference in length = 12.57 - 10.47 = 2.1cm (1 d.p.)
Answer: 2.1cm
G=.74f, where f is the initial price and g is the sale price
Answer:
Step-by-step explanation:
B= -20+45/56
B=-20.80
Answer:
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Step-by-step explanation:
Given data
mean = 5.1 millimeters (mm)
standard deviation = 0.7 mm
to find out
percent (%) of ancient prehistoric thinner than 3
solution
we have given mean and SD
so Z will be = x -mean / SD
Z = ( x - 5.1 ) / 0.7
so P( x < 3 ) = P ( (x - 5.1 ) / 0.7 < ( 3 - 5.1 ) / 0.7 )
P( Z = ( 3 - 5.1 ) / 1.5 )
P( Z = -3 ) = 0.0013
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Answer: c
Step-by-step explanation:
You can take the blank as x
so 361.2 / x = 36.12
multiply by x
361.2 = 36.12x
divide
x = 10
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