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3 years ago

Which monomial is a perfect cube?

Mathematics

2 answers:

neonofarm [45]3 years ago

5 0

Answer:

Option (a) is correct.

$1x^3$ is a perfect cube.

Step-by-step explanation:

Given : Some Monomial

We have to choose out of given monomial that is a perfect cube.

Perfect cubes are numbers that can be written as $(ab)^3$

So, consider $1x^3$ , we know 1 can be written as $1^3$

Thus, $1x^3$ can be written as $1^3x^3=(1x)^3$

Thus, Option (a) is correct.

fenix001 [56]3 years ago

4 0

Answer:

Option A is correct

$1x^3$

Step-by-step explanation:

Perfect cube is a number that is the cube of any integer number.

For example:

$7^3 = 343$

$(ab)^3 = a^3b^3$

From the given options we have to find which monomial is a perfect cube.

Consider the monomial $1x^3$ .

We can write 1 as:

$1 = 1 \cdot 1 \cdot 1 = 1^3$

It can be written as:

$1x^3 = 1^3 \cdot x^3 = (1x)^3$

Therefore, $1x^3$ monomial is a perfect cube

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The division algorithm states that if p(x) and d(x) are polynomial functions with d left parenthesis x right parenthesis not e

katrin [286]

Answer:

In a division algorithm, $p(x)$ refers to the dividend polynomial, $d(x)$ refers to the divisor polynomial, $q(x)$ refers to the quotient polynomial and $r(x)$ refers to the residula polynomial.

The division algorithm is defined as

$p(x)=d(x) \times q(x) +r(x)$

Where $p(x)\geq d(x)$ and $d(x) \neq 0$ , other wise the algorithm won't be defined.

So, the complete paragraph is: "if $p(x)$ and $d(x)$ are polynomial functions with $d(x)\neq 0$ and the degree of $d(x)$ is less than or equal to the degree of $p(x)$ , then there exist unique polynomial functions $q(x)$ and $r(x)$ such that $p(x)=d(x) \times q(x) +r(x)$ .