Center of the circle: C=(3,8)=(h,k)→h=3, k=8
Radius of the circle: r=5
Standard form of the equation for the circle:
(x-h)^2+(y-k)^2=r^2
(x-3)^2+(y-8)^2=5^2
(x-3)^2+(y-8)^2=25
General for of the equation for the circle:
(x)^2-2(x)(3)+(3)^2+(y)^2-2(y)(8)+(8)^2=25
x^2-6x+9+y^2-16y+64=25
x^2+y^2-6x-16y+73=25
x^2+y^2-6x-16y+73-25=25-25
x^2+y^2-6x-16y+48=0
Answer: The general form of the equation for the circle is:
x^2+y^2-6x-16y+48=0
Step-by-step explanation:
1. 154 ( as ( - ) ( - ) = ( + )
2. option B is correct
3. - 29
4. 26
5. 60
6. 1
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Answer:
AB=30
AC=22.5
Step-by-step explanation:
8/15=12/x
x=22.5 (AC)
8/15=16/x
x=30 (AB)
I a pretty sure it is 228,000 but i am not sure.
Answer:
v=3i+8j
Step-by-step explanation:
The given the vector v has an initial point (-2,-6) and a terminal point of (1,2).
To find the components of vector v, we subtract the terminal points from the initial point to obtain.
v=<1,2>-<-2,-6>
v=<1--2,2--6>
v=<1+2,2+6>
v=<3,8>
As a linear combination of the standard unit vectors.
v=3i+8j
