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3 years ago

The Australian government increased the number of marine sanctuaries. The protected area

Mathematics

1 answer:

laila [671]3 years ago

3 0

Answer:

Step-by-step explanation:

10x10x10x10x10x10=1000000x1.2=1200000

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Find the point on the graph of 2x+3y=12 where x=3

mafiozo [28]

Answer:

(3,2)

Step-by-step explanation:

2x+3y=12

substitute x with 3 because x=3

2(3)+3y=12

multiply

6+3y=12

(subtract 6 from both sides)

3y=6

(divide by 3 on both sides)

1y=2

x = 3 and y = 2

3 0

3 years ago

Read 2 more answers

Which equation could be used to find the cost of each Apple? 4x+3(0.89)=$7.15 , 3x+4(0.89)=$7.15 , $7.15-3x=0.89 , or 4x-3(0.89)

Dmitry_Shevchenko [17]

Step-by-step explanation:

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5 0

3 years ago

Misha used 1/4 of a carton of 12 eggs to make a omelet.How many eggs did she use?

nadya68 [22]

So 1/4 of 12 is
'of' can be translated to multiply so
1/4 times 12=12/4=3

she used 3 eggs
B is the answer

8 0

3 years ago

Read 2 more answers

There are not asymptotes for the parent function<br> f (x) =1/x <br> True<br> False

Georgia [21]

Answer:

True

Step-by-step explanation:

the parent function f(x) = 1/x has a vertical asymptote at x = 0 and a horizontal asymptote at y = 0

4 0

3 years ago

6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP

adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = $360^{o}$ - $324^{o}$

= 0 $36^{o}$

Sum of angles in a triangle = $180^{o}$

<P + <Q + <S = $180^{o}$

048° + 0 $36^{o}$ + <S = $180^{o}$

$84^{o}$ + <S = $180^{o}$

<S = $180^{o}$ - $84^{o}$

= $96^{o}$

<S = $96^{o}$

Applying the Sine rule,

$\frac{y}{Sin P}$ = $\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin P}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin 48^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{y}{0.74314}$ = $\frac{17}{0.99452}$

⇒ y = $\frac{12.63338}{0.99452}$

= 12.703

y = 12.70 km

$\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{x}{Sin 36^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{x}{0.58779}$ = $\frac{17}{0.99452}$

⇒ x = $\frac{9.992430}{0.99452}$

= 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

6 0

3 years ago