Step-by-step explanation:
Step 1: Calculate the mean. Step 2: Calculate how far away each data point is from the mean using positive distances. These are called absolute deviations. Step 3: Add those deviations together. Step 4: Divide the sum by the number of data points.
Answer:
0.0064
0.00032
Step-by-step explanation:
Given the details:
P(X > 3), n = 5, p = 0.2
The binomial distribution is related using the formula:
P(x = x) = nCx * p^x * q^(n-x)
q = 1 - p = 1 - 0.2 = 0.8
P(X > 3) = p(x = 4) + p(x = 5)
P(x = 4) = 5C4 * 0.2^4 * 0.8^1 = 5 * 0.2^4 * 0.8^1 = 0.0064
P(x = 5) = 5C5 * 0.2^5 * 0.8^0 = 1 * 0.2^5 * 0.8^0 = 0.00032
Step-by-step explanation:
Claim: There's 14 Goats and 9 Chickens!!
Data:
Working with the Provided Information.
Let the Number of goats be x
let the Number of Chickens be y
x + y = 23..... (i)
Since the goat Possesses Two Pair of Legs... Which is a Total of 4 Legs... We say Let its Contribution be 4x.
The Chicken has Only a Pair Of Legs...Which is a total of 2 legs.... We say let its contribution be 2y
4x + 2y = 74 .....(ii)
BRINGING BOTH EQUATIONS TOGETHER.
x + y = 23
4x + 2y = 74
From Eqn i
x= 23 - y
Substitute into eqn ii
4(23 - y ) + 2y = 74
92 - 4y + 2y = 74
92 - 2y = 74
2y = 92 - 74
2y = 18
y= 9.
Substitute y into any of the eqns to get x
x + y = 23
x + 9=23
x = 23 - 9
x = 14
This simply proves that there are 14 Goats and 9 Chickens!!!.
HAVE A GREAT DAY!
Answer:
Step-by-step explanation:
r-13,725 <_ 1650
r-<_ 15,375
r-13725>_-1650
r >_12,125
Tuition could be between $12,125 and $15,375
PLS MARK ME AS BRAINLIEST
27 x 1.25= 33.75
5 x 1.99=9.95
1 x 1.50= 1.50
add that up =45.2
/26 students = 1.73 dollars
