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Stells [14]
3 years ago
8

For each triangle shown below, determine whether you would use the Law of Sines or Law of Cosines to find angle x. Then find ang

le x to the nearest tenth.
A 90.1 by The Law of Sines (SAS)
B. 75.6 by The Law of Cosines (SAS)
C. 46.9 by The Law of Cosines (SSS)
D. 37.2 by The Law of Sines (SSA)

Mathematics
1 answer:
GalinKa [24]3 years ago
3 0
For the question above we can use the law of sine that states;

a/sinA = b/sinB = c/sinC
 Where a is the opposite side of angle A
             b is the opposite side of angle B
             c is the opposite side of angle C

x/sin63 = 65/sin40

x = 65(sin63)/sin40

   = 57.9154/0.6429
     = 90.10

The answer is <span>A) 90.1 by The Law of Sines (SAS)</span>
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Aleonysh [2.5K]

Answer:

No Solution

Step-by-step explanation:

8x+2y=13                         4x+y=11               Subtract 4x on both sides to isolate y

                                        y=-4x+11       <---- Substitute this equation into the                                            

                                                                     equation 8x+2y=13

8x+2(-4x+11)=13

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No Solution          

                     

4 0
3 years ago
How do you solve the equation 2cos^2 - cosx = 0 for all solutions?
exis [7]

Answer:

<em>π/2 and π/3</em>

Step-by-step explanation:

Given the equation 2cos²x - cosx = 0, to find the solution to the equation, we will follow the following step.

let P = cosx

The equation becomes 2P²-P = 0

P(2P-1) = 0

P = 0 and 2P-1 = 0

P= 0 and P = 1/2

Since P = cosx

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If cos(x) = 0

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If cos(x) = 1/2

x = cos⁻¹1/2

x = 60⁰

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<em>Hence the solutions to the equation are π/2 and π/3.</em>

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3 years ago
V
aleksley [76]

Answer:

a=1.66

b=8368.12

Step-by-step explanation:

hope it helps

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