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geniusboy [140]
3 years ago
15

What is area of this shape

Mathematics
1 answer:
german3 years ago
5 0

Answer:

132 ft squared

Step-by-step explanation:

One way is to divide the shape into a rectangle and a triangle, by drawing a vertical line.

This gives a rectangle that is 9 by 11, so has area 99.

The triangle has a base of 11 and height of 15 - 9 = 6.

So the area of the triangle = 1/2 x b x h = 1/2 x 11 x 6 = 33

So the total area is 99 + 33 = 132.

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At the parents evening the ratio of mums to dads was 3:2. Out of 500 appointments how many were with mums?
guajiro [1.7K]

Answer:

300

Step-by-step explanation:

Sum the parts of the ratio : 3 + 2 = 5 parts

Divide the number of appointments by 5 to find the value of one part of the ratio, that is

\frac{500}{5} = 100 ← value of 1 part of the ratio

The mums consisted of 3 parts, hence

3 × 100 = 300 ← appointments with mums

3 0
3 years ago
Identify the phase shift of each function. Describe each phase shift use a phrase like 3 units to the left
melisa1 [442]

Answer:

It moves horizontally 1/2 units to the left

It moves vertically 2 units up

Step-by-step explanation:

∵ y = Acos(Bx - C) + D

∵ y = 2 - 3cos(2x + 1)

∴ The phrase of shift:

∵ The horizontally shift is -C/B = - 1/2 = -1/2

∴ It moves 1/2 units to the left

∵ The vertically shift is D

∴ It moves 2 units up

7 0
3 years ago
Please help.<br> Is algebra.
Vlad1618 [11]
? = 2. Thats the only one i got that equals 8xy^2. Not sure if its right tho.
4 0
3 years ago
Read 2 more answers
Find the point(s) in which f(x)=e^5-2x and y=6 intercept
Nana76 [90]

Answer:

(1.6, 6)

Step-by-step explanation:

ln({e}^{5 - 2x}  = 6)

5 - 2x =  ln(6)

2x = 5 -  ln(6)

x =  \frac{5 -  ln(6) }{2}

y = 6

7 0
3 years ago
Which is the focus of a parabola with equation y2 = 4x?
statuscvo [17]

Answer:

(1, 0)

Step-by-step explanation:

Please write this as y^2 = 4x; the " ^ " indicates exponentiation.

The appropriate equation for a horizontal parabola that opens to the right is

y^2 = 4px

Here, we are told that  y^2 = 4x; this tells us that 4p = 4, and so p = 1.  

Again, this parabola is a horizontal one and it opens to the right.  p = 1 is the distance of the focus from the vertex, and in this case p = 1.  Thus, the focus is at (1, 0) (situated on the x-axis).

6 0
3 years ago
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