OPTIONS:
a. When there are just two other people at the party.
b. When everyone is wearing a nametag.
c. When there are more than 50 people attending the same party.
d. When the need for help from the person who is having a heart attack is very clear
Answer:
c. When there are more than 50 people attending the same party.
Explanation:
Bystander effect is a term used in social psychology to describe the tendency of an individual to intervene in the event of an emergency to offer help to the person needing it, when others are present at the scene of the emergency.
In the case of an emergency just like the scenario stated in the question, where someone develops a heart attack at a dance party, if the party has more people, the slimmer the chance of the person getting help from any of the 50 people at the party, as the presence of others would tend to discourage the any individual from attempting to help the victim having the heart attack.
The situation that would more likely show the bystander intervention effect is <em>"c. When there are more than 50 people attending the same party."</em>
Explanation:
The valence electrons determine the group the elements belong in the periodic table. For example, the element sodium, Na, has a valence electron of one and so it belongs to Group 1 in the periodic table. Another example is Aluminium, Al, which has a valence electron of three and therefore it belongs to Group 3 in the periodic table.
The answer is carbohydrate
For radioactive materials with short half-lives, you use a very sensitive calibrated detector to measure how many counts per second it is producing. Then using the exact same set up you do the same at a latter time. You use the two readings and the time between them to determine the half-life. You don’t have to wait exactly a half-life, you can do the math with any significant time difference. Also, you don’t need to know the absolute radioactivity, as long as the set up is the same you only need to know fraction by which it changed.
For radioactive materials with long half-lives that won’t work. Instead you approach the problem differently. You precisely measure the mass of a very pure sample of the radioactive material. You can use that to calculate the number of atoms in the sample. Then you put the sample in a counter that is calibrated to determine the absolute number of disintegrations happening in a given time. Now you know how many of them are disintegrating every second. You use the following equations:
Decays per Second = (Number of Atoms) x (Decay Constant)
Half-life = (Natural Log of 2) / (Decay Constant)
And you can calculate the half-life
Hope it helps :)
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