In tissue from the intestinal epithelium of a frog, the following proportions of cells were found at each stage of the cell cycl
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Answer:
The answer is 83.38%.
Explanation:
The probability of young children having blood levels that impair their neurological development is given as 60% in the question. To find the probability of at least 5 children out of 10 in a sample having said blood levels, we need to use the binomial probability.
n represents the total number of children in the sample so n = 10 and p is the probability of the children having blood levels causing the problem which is 60% so p = 0.6.
We want the probability of it being observed for 5 or more children and that is . If we subtract the
from 1, which is the probability of not observing the condition in 5 or more children, we will have the
.
which are the probability range in the function, the sample size and the probability of observing the condition respectively.
The result is 1 - 0.1662 = 0.8338 which means that the probability that is asked is 83.38%.
I hope this answer helps.