Answer:
Given: The radius of circle C is 6 units and the measure of central angle ACB is StartFraction pi Over 2 EndFraction radians.
What is the approximate area of the entire circle?
113 square units
What is the approximate area of the entire sector created by central angle ACB?
28 square units
What is the approximate area of the shaded region only?
22 square units
The volume is 214*8*2012
=3,444,544
Use Pythagorean theorem.
[tex]|ON|^2+|MN|^2=|OM|^2\\\\x^2+x^2=8^2\\\\2x^2=64\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=32\to x=\sqrt{32}\\\\x=\sqrt{16\cdot2}\\\\x=\sqrt{16}\cdot\sqrt2\\\\\boxed{x=4\sqrt2}
Answer: |MN| = 4√2.
First change 0.8 to a fraction which is 4/5. Then find a common denominator between 5/8, 4/5, and 3/5. The common denominator is 40. So then you multiply the numerator by the same number you multiply the denominator by. I'll do 5/8 as an example; to get 40 as your denominator multiply 8 by 5, and then multiply 5 by 5. The fraction you'll get is 25/40. The rest of the fractions are 4/5 - 32/40 and 3/5 - 24/40. Then order them either from smallest to largest (24/40, 25/40, 32/40) or largest to smallest (32/40, 25/40, 24/40).
2hr=$12
1hr=12/2= $6/hr
$36=1hr/$6= 6hr for $36
If he worked 3hr he would get (6*3)= $18
If he worked 4 hours he would get (6*4)= $24
I hope this answers your question
