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miss Akunina [59]
3 years ago
15

What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?

Mathematics
1 answer:
andriy [413]3 years ago
3 0

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5)  and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)  

To Find:

M(x₄ ,y₄) = ?  and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

As M is the mid point of PR and N is the mid point of RQ so we will have

Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})

Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})

Substituting the given value in above equation we get

Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)

Similarly,

Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)

∴ M(x₄ ,y₄) = (-3.5 , 0.5)  and

  N (x₅ ,y₅) = ( -1 , -0.5 )

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n engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that
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Answer:

<em>The calculated t- value =  1.11 > 2.89 at 0.025 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The engineer designed the valve such that it would produce a mean pressure is not equal to  5.4</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the Population (μ) = 5.4</em>

<em>Given sample size 'n' = 9</em>

<em>Mean of the sample (x⁻) = 5.7</em>

<em>Standard deviation of the sample (s) = 0.81</em>

<u><em>Step(ii):-</em></u>

<em>Null Hypothesis: H₀:</em>  The engineer designed the valve such that it would produce a mean pressure of 5.4

H₀: μ = 5.4

<em>Alternative Hypothesis : H₁:</em>  μ ≠ 5.4

Level of significance = 0.025

Test statistic

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           t = \frac{5.7 -5.4}{\frac{0.81}{\sqrt{9} } }

         t = 1.11

<em>Degrees of freedom </em>

<em>ν = n-1 = 9-1 =8</em>

t₀.₀₁₅ , ₈  = 2.89

<em>The calculated t- value =  1.11 > 2.89 at 0.025 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The engineer designed the valve such that it would produce a mean pressure is not equal to  5.4</em>

<em></em>

<em />

7 0
3 years ago
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