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miss Akunina [59]
3 years ago
15

What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?

Mathematics
1 answer:
andriy [413]3 years ago
3 0

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5)  and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)  

To Find:

M(x₄ ,y₄) = ?  and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

As M is the mid point of PR and N is the mid point of RQ so we will have

Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})

Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})

Substituting the given value in above equation we get

Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)

Similarly,

Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)

∴ M(x₄ ,y₄) = (-3.5 , 0.5)  and

  N (x₅ ,y₅) = ( -1 , -0.5 )

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Two rectangles are shown below. Rectangle P has a perimeter of 20 inches.
arsen [322]

Answer:

c) j=2 and h=4

Step-by-step explanation:

h+h+j+4+j+4=20

3h+3h+j+1+j+1=30

2h+2j+8=20

6h+2j+2=30

multiply the first equation by -3

-6h-6j-24=-60  

this equals

-6h-6j=-36

6h+2j=28

-4j=-8

j=2

Since j=2

2h+2(2)+8=20

2h+12=20

2h=8

h=4

3 0
2 years ago
A bag contains 4 red, 5 blue, and 6 green marbles: ​One blue marble is selected and NOT replaced. If a 2nd marble is drawn, what
cupoosta [38]

Answer:

2/7

Step-by-step explanation:

To find the this first you need the total number of marbles minus one since the blue marble was taken.

4+5+6-1=14

after one blue marble being picked there are 4 blue left, so the fraction is

4/14 and after being simplified it is 2/7

8 0
3 years ago
Read 2 more answers
9.
siniylev [52]

Answer:

Slant height (s)= 12.1 cm

Step-by-step explanation:

Given: Base= 4.5 cm.

           Surface area of right square pyramid= 129.5 cm.

First, calculating slant height (s) of right square pyramid.

Surface area of square pyramid= (a^{2} +2\times a\times s)

a= side of square base.

s= slant height

∴ 129.5= (4.5^{2} + 2\times 4.5\times s)

⇒ 129.5= (20.25+2\times 4.5\times s)

⇒ 129.5= (20.25+9\times s)

Now, opening the parenthesis and subtracting both side by 20.25.

⇒ 109.25=9\times s

cross multiplying both side

∴ Slant height (s)= 12.1

5 0
3 years ago
Which table represents a direct variation? Table A x 4 6 8 10 y 7 9 11 13 Table B x 4 6 8 10 y 12 18 24 30 Table C x 4 6 8 10 y
Greeley [361]

Answer:

We conclude that 'Table B' represents a direct variation.

Step-by-step explanation:

We know that when y varies directly with x, the equation is

y ∝ x

y = kx

k = y/x

where 'k' is called the constant of proportionality.

Table A

x     4 6 8 10

y     7 9 11 13

Finding k for all the pairs of x and y

k = y/x

k = 7/4, k = 9/6 = 3/2, k = 11 / 8, k = 13/11

As constant of proportionality 'k' does not remain constant.

Hence, table A does not represent a direct variation

Table B

x     4   6   8   10

y     12 18 24 30

Finding k all the pairs of x and y

k = y/x

k = 12/4 = 3, k = 18/6 = 3, k = 24/8 = 3, k = 30/10 = 3

As the constant of proportionality remains constant.

Therefore, the value of k = 3 for all the points in the table.

Hence, table B represents a direct variation.

Table C

x     4   6   8   10

y     1    3    5    7

Finding k all the pairs of x and y

k = y/x

k = 1/4, k = 3/6 = 1/2, k = 5/8, k = 7/10

As the constant of proportionality 'k' does not remain constant.

Hence, table C does not represent a direct variation.

Table D

x     4   6   8   10

y     3   3   3    3

Finding k all the pairs of x and y

k = y/x

k = 3/4, k = 3/6, k = 3/8, k = 3/10

As the constant of proportionality 'k' does not remain constant.

Hence, table D does not a direct variation.

Therefore, we conclude that 'Table B' represents a direct variation.

8 0
3 years ago
Read 2 more answers
A farmer has 520 feet of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one s
Setler [38]

Answer:

310\text{ feet and }210\text{ feet}

Step-by-step explanation:

GIVEN: A farmer has 520 \text{ feet} of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is 310 \text{ feet}.

TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.

SOLUTION:

Let the length of rectangle be x and y

perimeter of rectangular pen =2(x+y)=520\text{ feet}

                                                x+y=260

                                               y=260-x

area of rectangular pen =\text{length}\times\text{width}

                                       =xy

putting value of y

=x(260-x)

=260x-x^2

to maximize \frac{d \text{(area)}}{dx}=0

260-2x=0

x=130\text{ feet}

y=390\text{ feet}

but the dimensions must be lesser or equal to than that of barn.

therefore maximum length rectangular pen =310\text{ feet}

                              width of rectangular pen =210\text{ feet}

Maximum area of rectangular pen =310\times210=65100\text{ feet}^2

Hence maximum area of rectangular pen is 65100\text{ feet}^2 and dimensions are 310\text{ feet and }210\text{ feet}

5 0
3 years ago
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