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3 years ago

What is the 117th term in the sequence 1,5,9,13,...

Mathematics

2 answers:

Ivahew [28]3 years ago

7 0

Answer:

the 117th number value is-->582

Lynna [10]3 years ago

6 0

Answer:

465

Step-by-step explanation:

You can do 4n-3 as the equation and you get 4x117=468-3=465

I know it's correct because I had this question before :)

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Solve the equation. -5x + 2 = 67

masya89 [10]

The answer is x=-13
I hope the answer helps!

7 0

3 years ago

In a survey, 18 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped

schepotkina [342]

Answer: 99% confidence interval would be (45.74,54.26).

Step-by-step explanation:

Since we have given that

N = 18

Mean = $50

Standard deviation = $7

At 99% confidence level, z = 2.58

So, Interval would be

$\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=50\pm 2.58\times \dfrac{7}{\sqrt{18}}\\\\=50\pm 4.26\\\\=(50-4.26,50+4.26)\\\\=(45.74,54.26)$

Hence, 99% confidence interval would be (45.74,54.26).

8 0

4 years ago

Compare the pair of fractions. ( <,>,=) 3/4__5/6

Andrew [12]

Answer:

3/4 is less < than 5/6

Step-by-step explanation:

4 0

3 years ago

Plzzzzzzzzzzzzhelppppppppmeeeeeeee!

never [62]

Answer:

It is false

Step-by-step explanation:

it is 1/2 :))

7 0

3 years ago

Read 2 more answers

Solve using the quadratic formula 2x^2+x+67=0

telo118 [61]

Answer:

$\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Multiple Roots
Standard Form: ax² + bx + c = 0
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Root i = √-1

Step-by-step explanation:

Step 1: Define

Identify

2x² + x + 67 = 0

a = 2

b = 1

c = 67

Step 2: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-1 \pm \sqrt{1-4(2)(67)}}{2}$
[√Radical] Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1-536}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-1 \pm \sqrt{-535}}{2}$
[√Radical] Simplify: $\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$

3 0

3 years ago