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3 years ago

Solve the formula for v: A=Z+vg V=

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

6 0

Answer:

v = (A-Z)/g

Step-by-step explanation:

you would put A-Z over g

A = Z + vg

Subtraction property of equality

A-Z = vg

division property of equality

(A-Z)/g = v

Symmetric property of equality

v = (A-Z)/g

zmey [24]3 years ago

5 0

Answer:

(a-z)/g =v

Step-by-step explanation:

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What is the proportion of 2/5 = 8/x

natali 33 [55]

To find is out put it like this 2 8
5 x
you multiple so 2 times what eduals 8 then you take that and multiply by 5

4 0

3 years ago

An archaeologist at a dig sets up a coordinate system using string. Two similar artifacts are found one at position (1, 4) and t

myrzilka [38]

Given:

Positions of two artifacts are at points (1, 4) and (5, 2).

To find:

The distance between these two artifacts.

Solution:

Distance formula: The distance between two points is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, the distance between two points (1, 4) and (5, 2) is

$d=\sqrt{(5-1)^2+(2-4)^2}$

$d=\sqrt{(4)^2+(-2)^2}$

$d=\sqrt{16+4}$

$d=\sqrt{20}$

$d=4.4721359$

Round to the nearest tenth of a unit.

$d\approx 4.5$

Therefore, the distance between two artifacts is 4.5 units.

4 0

3 years ago

I cant remember how to do this

Scrat [10]

Answer:

z = 80°

Step-by-step explanation:

ABCD ~ FECG

∠F ≅ ∠A = z

∠F = 360-100-60-120=80

z = 80°

3 0

3 years ago

If $8700 is invested at 3% annual simple interest, how much should be invested at 6% annual simple interest so that the total ye

True [87]

First off, see how much 8700 as principal, yields at 3% APR
that is $\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}$

it will yield some amount

subtract that amount from 393
the difference is how much the yield will be on the 6% investment
so

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}
\\\\\\
\implies \boxed{?}\\\\
-----------------------------\\\\
\textit{how much to invest at 6\%?}
\\\\\\
$

$\bf \qquad \textit{Simple Interest Earned}\\\\
(393-\boxed{?}) = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
t=years\to &1
\end{cases}
\\\\\\
\textit{solve for "P", to see how much should the Principal be}\\\\
\textit{keep in mind that }P+\boxed{?}=393\leftarrow \textit{both yields added}$

6 0

3 years ago

Two angles are supplementary. One angle is 40° more

bulgar [2K]

Answer:

Let x = the measure of the smaller angle

Let 3x + 40 = the measure of the larger angle

x + 3x + 40 = 180

4x = 140

x = 35º

3x + 40 = 3(35) + 40 = 145º

Step-by-step explanation:

6 0

3 years ago