Answer:
Option B is correct.
![5\sqrt[3]{10} + 4\sqrt[3]{10}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B10%7D%20%2B%204%5Csqrt%5B3%5D%7B10%7D)
Step-by-step explanation:
Given the equation: ![9\sqrt[3]{10}](https://tex.z-dn.net/?f=9%5Csqrt%5B3%5D%7B10%7D)
We can write 9 as:
9 = 5+ 4
then;
![(5+4)\sqrt[3]{10}](https://tex.z-dn.net/?f=%285%2B4%29%5Csqrt%5B3%5D%7B10%7D)
Using distributive property:

Apply distributive property:
![5\sqrt[3]{10} + 4\sqrt[3]{10}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B10%7D%20%2B%204%5Csqrt%5B3%5D%7B10%7D)
Therefore, the expression which is equivalent to
is ![5\sqrt[3]{10} + 4\sqrt[3]{10}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B10%7D%20%2B%204%5Csqrt%5B3%5D%7B10%7D)
Answer:
3/4c so it has to be A im sure .
Two intersecting line segments forming an angle marked with a small box.
The "small box" represents 90°, and perpendicular lines are 2 intersecting lines that form 90° angles
Answer:
Solution given:
-2x²+7x-6=0
2x²-7x+6=0
Comparing above equation with ax²+bx+c
we get
a=2
b=-7
c=6
By using Vieta's theorem
X1+X2=
=
again
X1X2=
=
=3
Double every year
year one
4 times 2
year 2
4 times 2 times 2 aka 4 times 2^2
year 3
4 times 2 times 2 times 2 aka 4 times 2^3
obviously
at year 'n' the number of rabbits will be
4 times 2^n