Common Factors of 32 and 36
factors of 32 = 1, 2, 4, 8, 16 and 32
factors of 36 = 1, 2, 3, 4, 6, 9, 18, 36
<span>So the common </span>factors of 32 and 36 are 1, 2 and 4.
The greatest common factor is 4
Elimination:
7x - 3y = 20
5x + 3y = 16
(add)
12x = 36
÷ 12
x = 3
(5 × 3) + 3y = 16
15 + 3y = 16
- 15
3y = 1
÷ 3
y = 1/3
Substitution:
5x + 3y = 16
- 3y
5x = 16 - 3y
÷ 5
x = 3.2 - 0.6y
5(3.2 - 0.6y) + 3y = 16
16 - 3y + 3y = 16
16 = 16
- 16
6y = 0
÷ 6
y = 0
Sorry the substitution messed up for some reason, I'll fix it after I've answered the other question
Answer:
x=4
Step-by-step explanation:
Answer:
x = 1 or x = -5
Step-by-step explanation:
Solve for x over the integers:
8 abs(x + 2) - 6 = 5 abs(x + 2) + 3
Subtract 5 abs(x + 2) - 6 from both sides:
3 abs(x + 2) = 9
Divide both sides by 3:
abs(x + 2) = 3
Split the equation into two possible cases:
x + 2 = 3 or x + 2 = -3
Subtract 2 from both sides:
x = 1 or x + 2 = -3
Subtract 2 from both sides:
Answer: x = 1 or x = -5
So what you need to do is find the less he can use.
