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3 years ago

Based on the scatterplot, what is the best prediction of the foot length for a person who has a head diameter of 54 centimeters?

Mathematics

1 answer:

zimovet [89]3 years ago

8 0

Answer:

its kinda hard to see, sorry, im guessing its 30

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f(x)=3x^(4)-5x^(3)-5x^(2)+5x+2 The number 3 is an upper bound for the set of roots of this polynomial function True or False

Leona [35]

Answer: TRUE

Step-by-step explanation: The number 3 is an upper bound because use 3 as a multiplyer of each bcoefficient of the polynomial and at each multiple,subtract the next coefficient from it. if all result after subtraction show positive, then the number used is an upper bound. This method is known as the synthetic division.

3 3 -5 -5 5 2

0 9 12 21 78

3 4 7 26 80

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

Henry rolls a fair dice 42 times. How many times would Henry expect to roll a number greater than 5?

Sonja [21]

Answer:

7 times

Step-by-step explanation:

There is one number greater than 5 on a dice - that is the number 6.

So probability of throwing a six = 1/6.

So it is 42 * 1/6.

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3 years ago