Two isolated, concentric, conducting spherical shells have radii R1 = 0.500 m and R2 = 1.00 m, uniform charges q1 = +2.00 μC and
q2 = +1.00 μC, and negligible thicknesses. What is the magnitude of the electric field E at radial distance (a) r = 4.00 m, (b) r = 0.700 m, and (c) r = 0.200 m? With V = 0 at infinity, what is V at (d) r = 4.00 m, (e) r = 1.00 m, (f) r = 0.700 m, (g) r = 0.500 m, (h) r = 0.200 m, and (i) r = 0? ( j) Sketch E(r) and V(r
1 answer:
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Answer:
vector with direction equal to the axis X.
Explanation:
We use the Gauss Law and the superposition law in order to solve this problem.
<u>Superposition Law:</u> the Total Electric field is the sum of the electric field of the first infinite sheet and the Electric field of the second infinite sheet:
<u>Thanks Gauss Law</u> we know that the electric field of a infinite sheet with density of charge σ is:
Then:
This electric field has a direction in the axis perpendicular to the sheets, that means it has the same direction as the axis X.
The correct answer is: electrons/second
Explanation:
5A current is passing through the copper wire and the light bulb; it means that 5 Coulombs of charge per second is passing through the wire (as current = coulombs/second). To find the electrons per second, the following formula is used:
Electrons per second =