Answer:
Explanation:
From the given information:
The initial PE 
= m×g×h
= 5 kg × 9.81 m/s² × 10 m
= 490.5 J
The change in Potential energy P.E of the box is:
ΔP.E = 
ΔP.E = 0 -
ΔP.E = 
If we take a look at conservation of total energy for determining the change in the internal energy of the box;
this can be re-written as:
Here, K.E = 0
Also, 70% goes into raising the internal energy for the box;
Thus,
ΔU = 343.35 J
Thus, the magnitude of the increase is = 343.35 J
Answer:
2.345 would be the most precious because you have more numbers to work with and exact numbers
To solve this problem it is necessary to use the concepts of Force of a spring through Hooke's law, therefore,
Where,
k = Spring constant
x = Displacement
Initially our values are given,
PART A ) With this values we can calculate the spring constant rearranging the previous equation,
PART B) Since the constant is unique to the spring, we can now calculate the force through the new elongation (0.38cm), that is
Therefore the weight of another person is 265.79N.
<span>B?) Electric field E = q / (εo*A)
C) V = E*d = q*d / (εo*A)
D) V = q / C
so C = q / V = q * 1/V = q*εo*A / q*d = εo*A / d
I hope this helps! ^_^
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Gravity bulb of hydrometer is made heavier so that its centre of gravity remains very low, when it is floating in denser liquids.
