Question

Help with quadratic graphs asap!

Answer 1

x= -0.25 and 1.25

x = -0.5 and  1.5

x = 0 and 1

x = -0.375 and 1.625

Step-by-step explanation:

Given equation of the curve is

$y = 4x^2 -4x-1$

(i)

First equation $4x^2 -4x-1 =0$

Here y = 0

In  x-axis the value of y = 0

The graph cuts the x-axis at(-0.25,0) and (1.25,0)

So, x= -0.25 and 1.25

(ii)

$4x^2 -4x-1 =2$

here y = 2

The line y= 2 cuts the curve at (-0.5,2) and (1.5,2)

So, x = -0.5 and  1.5

Given equation of the curve is

$y= 3x^2-3x -1$

(i)

$3x^2-3x +2 =2$

$\Leftrightarrow 3x^2-3x -1 = -1$

Here y = -1

The line y = -1  cuts the curve at (0,-1) and (1,-1)

So x = 0 and 1

(ii)

$3x^2-3x -1 =x+1$

Here y = x+1

The line y -x =1 cuts the curve at (-0.375,0.5) and (1.625,2).

So x = -0.375 and 1.625