3 years ago

A system of linear equations is given by the tables.

Mathematics

1 answer:

almond37 [142]3 years ago

5 0

Answer:

-1

x=4,y=11 (same in both equations)

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Please help I am struggling please

Katen [24]

Answer:

x = 8sqrt3

y=8

Step-by-step explanation:

cos60=y/16

y=16cos60

y=16x1/2

y=8

sin60=x/16

x=16sin60

x=(16sqrt3)/2

x=8sqrt3

3 0

2 years ago

Is this correct ? Please help me

NNADVOKAT [17]

Answer:

Median: 8

Minimum: 3

Maximum: 15

First quartile: 6

Third quartile: 12.5

Interquartile Range: 6.5

Outliers: none

Step-by-step explanation:

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2 years ago

Please answer the question bellow

valentina_108 [34]

No solution

because delta ( b^2 - 4ac ) is lower than 0(zero) .

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2 years ago

a satellite's escape velocity is 6.5 mi/sec, the radius of the earth is 3960 mi, and the earth's gravitational constant is 32.2

Artyom0805 [142]

Answer:

$23.89x10^{6}$ ft

Step-by-step explanation:

$\frac{V^{2} }{R^{2} } = \frac{2g}{R+h} \\$ This is the formula to find satellite's escape velocity V , where R is earth's radius, h is the satellite's height from the earth surface and g is the earth's gravitational constant.

$R^{2}(R+h) \frac{V^{2} }{R^{2} } =R^{2} (R+h)\frac{2g}{R+h}$ (Multiplying to clear the fractions)

(R+h) $V^{2} =R^{2} 2g$

$R+h=\frac{2R^{2}g }{V^{2} }$

$h= \frac{2R^{2} g}{V^{2} } -R$

Now, we can determine height of satellite from the surface of the earth

by putting the values in above equation

$h= \frac{2 * (3960)^{2}*32.2 }{6.5^{2} } -3960\\h= 23.902 x10^{6} - 3960\\ h=23.89x10^{6} ft$

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3 years ago

Suppose scores on exams in statistics are normally distributed with an unknown population mean and a population standard deviati

Gnom [1K]

this the answer of queastions

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2 years ago

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