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2 years ago

What are the zeros of this function?

Mathematics

1 answer:

BabaBlast [244]2 years ago

3 0

Answer:

x = 0 and x = 6

Step-by-step explanation:

See the graph attached to this question.

It is clear from the graph that the curve touches x-axis i.e. y becomes zero at points x = 0 and x = 6

Therefore, the give parabola has zeros at x = 0 and x = 6. (Answer)

Zeros of a function y = f(x) are determined from the equation f(x) = 0 and solving it we will get the x-values which are the zeros of the function.

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What is the slope and the y-intercept of the graph of the linear function shown on the grid ?

VladimirAG [237]

Answer:

Slope: -1/4; Y-Intercept: 1.5

Step-by-step explanation:

Step 1: Find the slope. The best way to do this is to transform the two given points to y=mx+b form. When given two points, the best way to find the slope will be to do y2-y1/x2-x1. In this equation it would be -2-0/2+6, which is -2/8, simplified is -0.25 or -1/4. So we have the slope, which can determine the length of the line.

Step 2: Find the Y-Intercept. Finding the Y-intercept is so much simpler when given a graph, since all you have to do is find where the line goes through the y-axis, which in this case is (0,1.5), meaning that the y-intercept is 1.5 <em>(note: the y-intercept can also be found when x=0, for example (0,9).</em>

Hope this helped, good luck!

5 0

2 years ago

Read 2 more answers

Find the value x.<br> Need help....thank you

nikklg [1K]

Step-by-step explanation:

It is parallel to the third side and has a length equal to half the length of the third side.

x= 34/2= 17

x= 17

6 0

2 years ago

Given that f(x) = x + 3<br> a) Find f(2)

Nataly_w [17]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

In the above question, it is given that :

$\qquad \sf \boxed{ \sf f(x) = \frac{x + 3}{2} }$

A.) Find f(2) :

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{2 + 3}{2}$

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{5}{2}$

$\qquad \sf \dashrightarrow \: f(2) = 0.5$

B.) Find ${ \sf {f}^{-1}(x) }$ :

$\qquad \sf \dashrightarrow \: let \: y = f (x)$

so, we can write it as :

$\qquad \sf \dashrightarrow \: y = \dfrac{x + 3}{2}$

$\qquad \sf \dashrightarrow \: 2y = x + 3$

$\qquad \sf \dashrightarrow \: x = 2y - 3$

Now, put x = ${ \sf {f}^{-1}(x) }$ , and y = x and we will get our required inverse function ~

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3$

C.) Find ${ \sf {f}^{-1}(12) }$ :

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 36- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 33$

7 0

8 months ago

What is the area of this figure?

Dima020 [189]

Answer:

$220.5 \: {yd}^{2}$

Step-by-step explanation:

Area of the figure = Area of the arc with radius 10 yd and central angle 90° + Area of rectangle with dimensions (10 + 5 - 3 = 12) 12 yd and (7 + 6 - 4 = 9) 9 yd + Area of square with dimension 4yd + Area of rectangle with dimensions 3 yd by 2 yd + Area of triangle with base 3 yd and height (5 + 3 = 8) 8 yd.

$= \frac{90 \degree}{360 \degree} \times 3.14 {(10)}^{2} + 12 \times 9 + {4}^{2} \\ + 3 \times 2 + \frac{1}{2} \times 3 \times 8 \\ \\ = \frac{1}{4} \times 314 + 108 + 16 + 6 + 12 \\ \\ = 78.5 + 142 \\ \\ = 220.5 \: {yd}^{2}$

4 0

2 years ago

I GIVE BRAINLIEST PLS IM TIMED!

vodomira [7]

Answer:

Step-by-step explanation:

Because you it is a function of the minutes, and not the hour, the answer is A.

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2 years ago