There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
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Answer:
Option (d).
Step-by-step explanation:
Note: The base of log is missing in h(x).
Consider the given functions are
The function m(x) can be written as
...(1)
The translation is defined as
.... (2)
Where, a is horizontal shift and b is vertical shift.
If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.
On comparing (1) and (2), we get
Therefore, we have to translate each point of the graph of h(x) 3 units left to get the graph of m(x).
Hence, option (d) is correct.
Answer:
I would multiply the first equation by −4 and the second by 3 and add together the two equatins (in columns): ... Step 2. Prepare the equations. Multiply every term in each equation by a ... Subtract Equation (4) from Equation (3). ... How do you solve the system 5x−10y=15 and 3x−2y=3 by multiplication?
Answer:
3x the second one
Step-by-step explanation:
