The time taken by the stone to reach the ground is option A 5.27 seconds.
Given,
The function; y = -16t² + 444
y is the height in feet
t is the time in seconds
A stone from y height is dropped from the edge of a vertical cliff.
We have to find the time taken by the stone to reach the ground;
Here,
y = -16t² + 444
y = 0
Then,
0 = -16t² + 444
16t² = 444
t² = 444/16
t² = 27.75
t = √27.75
t = 5.27 seconds
That is,
The time taken by the stone to reach the ground is option A 5.27 seconds.
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Answer:
101.85ft
Step-by-step explanation:
We can use tan here

Answer:
36
Step-by-step explanation:
N = 6
S = 0 n = 1
2(1) - 1 = 1
S = 0 + 1 = 1
n = n + 1
n = 1 + 1
n = 2
S = 1 n = 2
2(2) - 1 = 3
S = 1 + 3 = 4
n = n + 1
n = 2 + 1
n = 3
S = 4 n = 3
2(3) - 1 = 5
S = 4 + 5 = 9
n = n + 1
n = 3 + 1
n = 4
S = 9 n = 4
2(4) - 1 = 7
S = 9 + 7 = 16
n = n + 1
n = 4 + 1
n = 5
S = 16 n = 5
2(5) - 1 = 9
S = 16 + 9 = 25
n = n + 1
n = 5 + 1
n = 6
S = 25 n = 6
2(6) - 1 = 11
S = 25 + 11 = 36
n = n + 1
n = 6 + 1
n = 7 > N
Stop
Point A is at (12,12)
Point B is at (48,24)
Use the distance formula √((x2-x1)^2 + (y2-y1)^2)
Length = √((48-12)^2 + (24-12)^2)
Length = √(36^2 + 12^2)
Length = √(1296 + 144)
Length = √1440
The answer is E.
306% of 25
= (306/100) * 25
= 3.06 * 25
= 76.5