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Anna [14]
3 years ago
11

Can you help me, friends, please?

Mathematics
1 answer:
Lilit [14]3 years ago
8 0

Answer:

slope: -3

y-intercept: 3

y = -3x +3

Step-by-step explanation:

Hint: Use the Desmos Graphing Caculator for liner equaions!

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Which point satisfies the system of equations y = 3x − 2 and y = -2x + 3?
Elodia [21]

Meet of lines: y = 3x − 2  and  y = -2x + 3?

y=3x-2 has slope 3 and y intercept -2 (which means thru (0,-2)) , so that's the blue line through point D.

y=-3x+3 has slope -2 and y intercept 3, so the red line through points A, C and  D.

The point D(1,1) is the intersection of the lines.  Let's check that algebraically:

3x-2=3(1)-2=1=y, good

-2x+3 = -2(1)+3=1=y, good

Answer: D

8 0
3 years ago
A concert was attended by 250 people if 30% of the people went to the basketball game, how many people went to the basketball ga
KonstantinChe [14]

Answer:

75

Step-by-step explanation:

6 0
3 years ago
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100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
The number y of Northern Rocky Mountain wolf breeding pairs x years since 1995 can
Alexus [3.1K]

Answer:

Step-by-step explanation:

7 0
2 years ago
Solve 3x−5 = 9. <br> x = −3 <br> x = 2 <br> x = 7 <br> x = 8
Nina [5.8K]

Solve 3x−5 = 9:


Add 5 to both sides, to isolate 3x on the left side: 3x = 5+9 = 14


Solve this for x: x = 14/3

7 0
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