Question

(ii) A peacock is sitting on the tree and observes its prey on

Answer 1

Answer:

74.8 m

Step-by-step explanation:

We are given that

$\theta=22^{\circ}$

Speed of peacock,v=10 km/h

Time,t=1 min 12 sec=60+12=72 s=$\frac{72}{3600}=0.02 h$

1 hour=3600 s

Distance=vt=$10\times 0.02=0.2 km=0.2\times 1000=200 m$

Using 1 km=1000 m

We know that

$sin\theta=\frac{Perpendicular\;side}{hypotenuse}$

Using the formula

$sin22=\frac{h}{200}$

$h=200sin22=200\times 0.374=74.8 m$

Hence, the peacock was at height  of 74.8 m on the tree.