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3 years ago

Can someone help me with this question?

Mathematics

2 answers:

WITCHER [35]3 years ago

8 0

Answer:

8/2

Step-by-step explanation:

I did the quizz and I got it correct

german3 years ago

3 0

Answer:

8/2

Step-by-step explanation:

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Please help me on this. you need to match the terms to the correct number.

Gnom [1K]

Answer:

64=8

49=7

36=6

25=5

100=10

16=4

9=3

20=4.5

4=2

1=1

67=8.2

81=9

5 0

3 years ago

Jenny studied the characteristics of two species of bacteria. The number of bacteria of species A, A(t), after t hours is repres

fredd [130]

Answer: D . $N(t) = 3 + (0.25t)^3 - 8(1.06)^t$

Step-by-step explanation:

Given : Jenny studied the characteristics of two species of bacteria. The number of bacteria of species A, A(t), after t hours is represented by the function,

$A(t) = 5 + (0.25t)^3$

The number of bacteria of species B, B(t), after t hours is represented by the function, $B(t) = 2 + 8(1.06)^t$

Then, the difference in the number of bacteria, N(t), of both the species after t hours will be :-

$N(t)=A(t)-B(t)\\\\=5 + (0.25t)^3-(2 + 8(1.06)^t)\\\\=5 + (0.25t)^3-2-8(1.06)^t\\\\=5-2 +(0.25t)^3-8(1.06)^t\\\\=3+(0.25t)^3-8(1.06)^t$

Hence, the correct answer should be : D . $N(t) = 3 + (0.25t)^3 - 8(1.06)^t$

7 0

4 years ago

getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.

blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies. Half of celias candies is equal to 2/3 of emmas candies.

They had a total of 105 candies altogether.

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

$\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}$

Hence, candies with celias and emmas is 60 and 45 respectively.

4 0

3 years ago

Determine the solution set of (2x - 5)2 = 11.

zhenek [66]

I think what you meant was

(2x - 5)² = 11 -- (1)

Square root both sides of (1), i.e.

√(2x - 5)² = ± √11 -- (2)

From (2), we have

2x - 5 = ± √11 -- (3)

By adding 5 to both sides in (3), we have

2x = 5 ± √11 -- (4)

Divide both sides of (4) by 2, and we obtain

x = (5 ± √11)/2 -- (5)

From (5), the solution set of (1) is

x = (5 + √11)/2, (5 - √11)/2 ...Ans.

8 0

3 years ago

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An ancient Roman coin is found and a curious anthropologist wishes to determine if the coin is fair— Fair meaning that when flip

Mamont248 [21]

The coin wouldn't be fair, because it landed on heads 72/100 times. If the coin was fair, the results should be equivalent to 1/2.

7 0

3 years ago

Read 2 more answers