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igomit [66]
3 years ago
7

A recipe for a potato salad calls for one teaspoon of vinegar for every two teaspoons of mayonnaise how many teaspoons of vinega

r are need for 16 teaspoons of mayonnaise
Mathematics
2 answers:
tekilochka [14]3 years ago
8 0

We can find this by doing 16/2

This is equal to 8

The answer is you need 8 teaspoons of vinegar for 16 tsp of mayonnaise

vlabodo [156]3 years ago
6 0
16÷2=8
8 teaspoons of vinegar
(honestly, that sounds disgusting)
(that is also a bad measurement tool)
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Elina [12.6K]

Answer:

what grade

Step-by-step explanation:

7 0
3 years ago
Camile is packing seeds to send to her mother in law. She estimates that she needs a box with a volume of at least 6,856 cubic i
jekas [21]

Step-by-step explanation:

the volume of a box (or prism) is always

length × width × height

so, box A

13 × 12 × 16 = 2,496 in³

box B

18 × 25 × 16 = 7,200 in³

box C

12 × 14 × 22 = 3,696 in³

box D

20 × 22 × 17 = 7,480 in³

so, she can use B or D.

5 0
1 year ago
Find the length BC
Nady [450]
Answer:

The length of BC = 12

Step-by-step explanation:

c^2 = a^2 + b^2

15^2 = 9^2 + b^2

225 = 81 + b^2

b^2 = 225 - 81

b^2 = 144

b = 12

The length of BC is 12
5 0
3 years ago
Respond pls <br> To get some points
Ipatiy [6.2K]
<h2>Answer:</h2>

1/2

<h2>Step-by-step explanation:</h2><h3>Known :</h3>
  • The school football team has a match tomorrow
  • The probability of the team winning is 1/6
  • The probability of the team drawing is 2/6

<h3>Asked :</h3>
  • The probability of the team losing

<h3>Solution :</h3>

Probability of the team losing the match = 1 - 1/6 - 2/6

Probability of the team losing the match = 6/6 - 1/6 - 2/6

Probability of the team losing the match = 3/6

Probability of the team losing the match = 1/2

<h3>Conclusion :</h3>

The probability of the team losing the match is 1/2

7 0
2 years ago
Help please! Will pick the Brainliest.<br> (sorry if it’s sideways)
KatRina [158]

1.

(x^2y^8)^\frac{2}{3}=x^{2\cdot\frac{2}{3}}y^{8\cdot\frac{2}{3}}=x^{\frac{4}{3}}y^{\frac{16}{3}}=x^{1\frac{1}{3}}y^{5\frac{1}{3}}=x^1x^\frac{1}{3}y^5y^\frac{1}{3}=xy^5\sqrt[3]{x}\sqrt[3]{y}=\boxed{xy^5\sqrt[3]{xy}}

Answer B)

2.

\frac{1}{3}\left(\frac{2}{15}x-\frac{2}{3}\right)>x+\frac{1}{5}\quad|\cdot3\\\\\\\frac{2}{15}x-\frac{2}{3}>3x+\frac{3}{5}\quad|\cdot15\\\\\\2x-\frac{30}{3}>45x+\frac{45}{5}\\\\2x-10>45x+9\\\\-10-9>45x-2x\\\\-19>43x\quad|:43\\\\\boxed{x

Answer B)

3.

\sqrt{14xy}\cdot\sqrt{12}\cdot\sqrt{30y}=\sqrt{14\cdot12\cdot30}\cdot\sqrt{xy^2}=\sqrt{2\cdot7\cdot3\cdot4\cdot2\cdot3\cdot5}\cdot\sqrt{xy^2}=\\\\=\sqrt{2^2\cdot3^2\cdot2^2\cdot5\cdot7}\cdot\sqrt{xy^2}=2\cdot3\cdot2\cdot\sqrt{35}\cdot y\cdot\sqrt{x}=\boxed{12y\sqrt{35x}}

3 0
3 years ago
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