Ask question

Ask question

All categories

2 years ago

12

The dot plot shows the ages of quiz show contestants. pg617069 Suppose a new data value, 30, is included in the dot plot. Which

statement describes the effect on the median? A The median would increase. B The median would equal the mean. C The median would stay the same. D The median would decrease.

2 answers:

soldier1979 [14.2K]2 years ago

8 0

Answer:

Step-by-step explanation:

A

Charra [1.4K]2 years ago

8 0

Answer:

The median would stay the same.

Step-by-step explanation:

You might be interested in

What is the equation of the graph below?

Molodets [167]

Answer:A

Step-by-step explanation:

look at the graph and u will find the same answer

6 0

3 years ago

Read 2 more answers

According to the graph, what is the value of the constant in the equation below?

Bogdan [553]

Answer:

D . 0.4

Step-by-step explanation:

let the height be the y coordinate

let the width be the x coordinate

first point :

width/x : 0.5

height/y : 0.8

according to the formula given:

height = constant/width :

so:

0.8 = constant/0.5

constant = 0.4

next point:

x : 0.8

y : 0.5

0.5 = constant/0.8

constant = 0.4

for all of the points, the constant is 0.4

5 0

3 years ago

The factors of x cube -10x square -53x-42

Verdich [7]

Answer:

<em><u></u></em> $x^3 - 10 x^2 -53x -42 = ( x + 1)(x + 3) (x - 14)$ <em><u></u></em>

Step-by-step explanation:

$x^3 - 10x^2 -53x - 42$

The factors of 42 : ±1 , ±2 , ±3 , ±6, ±7, ±14, ±21 , ±42

<u>Using trial and error method we will find the first root of the polynomial.</u>

1 : ( 1 )³ - 10 ( 1 )² - 53 ( 1 ) - 42

1 - 10 - 53 - 42 ≠ 0

Therefore 1 is not a root

-1 : ( -1 )³ - 10 (- 1 )² - 53 (- 1 ) - 42

- 1 - 10 + 53 - 42

53 - 53 = 0

Therefore - 1 is a root of the polynomial.

Therefore ( x + 1) is a factor.

<u>Now by long division or by using synthetic division we can find other factors.</u>

<u>Synthetic Division :</u>

-1 | 1 -10 -53 - 42

| 0 - 1 11 42

|______________________

1 - 11 - 42 0

Therefore ,

$x^3 - 10 x^2 -53x -42 = ( x + 1)(x^2 - 11x +42)$ ------ ( 1 )

<u>Next further factorize x² - 11x - 42</u>

x² - 11x - 42

= x² - 14x + 3x - 42

=x(x - 14) + 3 (x - 14)

=(x + 3 )(x - 14)

Therefore ,

$x^3 - 10 x^2 -53x -42 = ( x + 1)(x + 3) (x - 14)$

4 0

3 years ago

Four buses carrying 146 high school students arrive to Montreal. The buses carry, respectively, 32, 44, 28, and 42 students. One

Naily [24]

Answer:

The expected value of X is $E(X)=\frac{2754}{73} \approx 37.73$ and the variance of X is $Var(X)=\frac{226192}{5329} \approx 42.45$

The expected value of Y is $E(Y)=\frac{73}{2} \approx 36.5$ and the variance of Y is $Var(Y)=\frac{179}{4} \approx 44.75$

Step-by-step explanation:

(a) Let X be a discrete random variable with set of possible values D and probability mass function p(x). The expected value, denoted by E(X) or $\mu_x$ , is

$E(X)=\sum_{x\in D} x\cdot p(x)$

The probability mass function $p_{X}(x)$ of X is given by

$p_{X}(28)=\frac{28}{146} \\\\p_{X}(32)=\frac{32}{146} \\\\p_{X}(42)=\frac{42}{146} \\\\p_{X}(44)=\frac{44}{146}$

Since the bus driver is equally likely to drive any of the 4 buses, the probability mass function $p_{Y}(x)$ of Y is given by

$p_{Y}(28)=p_{Y}(32)=p_{Y}(42)=p_{Y}(44)=\frac{1}{4}$

The expected value of X is

$E(X)=\sum_{x\in [28,32,42,44]} x\cdot p_{X}(x)$

$E(X)=28\cdot \frac{28}{146}+32\cdot \frac{32}{146} +42\cdot \frac{42}{146} +44 \cdot \frac{44}{146}\\\\E(X)=\frac{392}{73}+\frac{512}{73}+\frac{882}{73}+\frac{968}{73}\\\\E(X)=\frac{2754}{73} \approx 37.73$

The expected value of Y is

$E(Y)=\sum_{x\in [28,32,42,44]} x\cdot p_{Y}(x)$

$E(Y)=28\cdot \frac{1}{4}+32\cdot \frac{1}{4} +42\cdot \frac{1}{4} +44 \cdot \frac{1}{4}\\\\E(Y)=146\cdot \frac{1}{4}\\\\E(Y)=\frac{73}{2} \approx 36.5$

(b) Let X have probability mass function p(x) and expected value E(X). Then the variance of X, denoted by V(X), is

$V(X)=\sum_{x\in D} (x-\mu)^2\cdot p(x)=E(X^2)-[E(X)]^2$

The variance of X is

$E(X^2)=\sum_{x\in [28,32,42,44]} x^2\cdot p_{X}(x)$

$E(X^2)=28^2\cdot \frac{28}{146}+32^2\cdot \frac{32}{146} +42^2\cdot \frac{42}{146} +44^2 \cdot \frac{44}{146}\\\\E(X^2)=\frac{10976}{73}+\frac{16384}{73}+\frac{37044}{73}+\frac{42592}{73}\\\\E(X^2)=\frac{106996}{73}$

$Var(X)=E(X^2)-(E(X))^2\\\\Var(X)=\frac{106996}{73}-(\frac{2754}{73})^2\\\\Var(X)=\frac{106996}{73}-\frac{7584516}{5329}\\\\Var(X)=\frac{7810708}{5329}-\frac{7584516}{5329}\\\\Var(X)=\frac{226192}{5329} \approx 42.45$

The variance of Y is

$E(Y^2)=\sum_{x\in [28,32,42,44]} x^2\cdot p_{Y}(x)$

$E(Y^2)=28^2\cdot \frac{1}{4}+32^2\cdot \frac{1}{4} +42^2\cdot \frac{1}{4} +44^2 \cdot \frac{1}{4}\\\\E(Y^2)=196+256+441+484\\\\E(Y^2)=1377$

$Var(Y)=E(Y^2)-(E(Y))^2\\\\Var(Y)=1377-(\frac{73}{2})^2\\\\Var(Y)=1377-\frac{5329}{4}\\\\Var(Y)=\frac{179}{4} \approx 44.75$

8 0

3 years ago

Please can someone help

V125BC [204]

Answer:

16/24 and 12/18, in simplest form 2/3

Step-by-step explanation:

8 parts juice

fruit and crushed ice = 3 + 9 = 12

ratio of juice to fruit and crushed ice is 8:12 or 8/12

8/12 (2/2) = 16/24

8/12 (1.5/1.5) = 12/18

in simplest form

8/12 (1/4 / 1/4) = 2/3

8 0

3 years ago