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Artemon [7]
3 years ago
12

You want to find out whether caffeine mitigates the effect of alcohol on reaction time. To study this, you administer to your su

bjects a drink that is equivalent to three 12-ounce beers, followed by the equivalent of two cups of coffee. Then your subjects complete a simulated driving task in which they must follow a fixed speed limit while driving on a straight road. Wind periodically and randomly pushes the simulated vehicle right, left, or not at all. Speed is measured in miles per hour above or below the 60-mph speed limit, with 1 mph being the smallest unit on the scale. Suppose the first subject scores 9 mph. Determine the real limits of 9. When measuring weight on a scale that is accurate to the nearest 0.2 pound, what are the real limits for the weight of 120 pounds? When measuring weight on a scale that is accurate to the nearest 0.5 pound, what are the real/limits for the we.ght of 187 pounds?
Mathematics
1 answer:
Ymorist [56]3 years ago
5 0

Answer:

First Question

lower limit of 9 mph  j =  8.5 \  mph

upper  limit of 9 mph q =  9.5 \  mph

Second Question

lower limit of 120 pounds is  i =  119.9 \  pounds

upper limit of 120 pounds is  l =  120.1 \  pounds

Third  Question

lower limit of 187 pounds is  a =  186.75 \  pounds

upper limit of 187 pounds is  b =  187.25 \  pounds  

Step-by-step explanation:

From the question we are told that

  The amount of beer administered is  three 12-ounce beers

  The  amount of coffee administered is  two cups of coffee

  The  speed limit is   60-mph

  The smallest unit of scale is  1 mph

  The first subject scores 9 mph

Generally given that the smallest unit of scale is  1 mph then the deviation of  9 mph will be by \frac{1}{2} \ mph

Hence the lower limit of 9 mph is

    j =  9 - 0.5

    j =  8.5 \  mph

And  the upper  limit of 9 mph is

    q =  9 + 0.5

    q =  9.5 \  mph    

Generally given that the measuring weight on a scale that is accurate to the nearest 0.2 pound then 120 pounds will deviate by  \frac{1}{0.2} \ pounds

Hence the lower limit of 120 pounds is

    i =  120 - 0.1

    i =  119.9 \  pounds

And  the upper  limit of 120 pounds is

    l =  120 + 0.1

    l =  120.1 \  pounds    

Generally given that the measuring weight on a scale that is accurate to the nearest 0.5 pound then  187 pounds will deviate by  \frac{1}{0.5} \ pounds = 0.25 \ pounds

Hence the lower limit of 120 pounds is

    a =  187 - 0.25

    a =  186.75 \  pounds

And  the upper  limit of 120 pounds is

    b =  187 + 0.25

    b =  187.25 \  pounds      

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