Question

You want to find out whether caffeine mitigates the effect of alcohol on reaction time. To study this, you administer to your subjects a drink that is equivalent to three 12-ounce beers, followed by the equivalent of two cups of coffee. Then your subjects complete a simulated driving task in which they must follow a fixed speed limit while driving on a straight road. Wind periodically and randomly pushes the simulated vehicle right, left, or not at all. Speed is measured in miles per hour above or below the 60-mph speed limit, with 1 mph being the smallest unit on the scale. Suppose the first subject scores 9 mph. Determine the real limits of 9. When measuring weight on a scale that is accurate to the nearest 0.2 pound, what are the real limits for the weight of 120 pounds? When measuring weight on a scale that is accurate to the nearest 0.5 pound, what are the real/limits for the we.ght of 187 pounds?

Answer 1

Answer:

First Question

lower limit of 9 mph  $j = 8.5 \ mph$

upper  limit of 9 mph $q = 9.5 \ mph$

Second Question

lower limit of 120 pounds is  $i = 119.9 \ pounds$

upper limit of 120 pounds is  $l = 120.1 \ pounds$

Third  Question

lower limit of 187 pounds is  $a = 186.75 \ pounds$

upper limit of 187 pounds is  $b = 187.25 \ pounds$  

Step-by-step explanation:

From the question we are told that

  The amount of beer administered is  three 12-ounce beers

  The  amount of coffee administered is  two cups of coffee

  The  speed limit is   60-mph

  The smallest unit of scale is  1 mph

  The first subject scores 9 mph

Generally given that the smallest unit of scale is  1 mph then the deviation of  9 mph will be by $\frac{1}{2} \ mph$

Hence the lower limit of 9 mph is

    $j = 9 - 0.5$

    $j = 8.5 \ mph$

And  the upper  limit of 9 mph is

    $q = 9 + 0.5$

    $q = 9.5 \ mph$    

Generally given that the measuring weight on a scale that is accurate to the nearest 0.2 pound then 120 pounds will deviate by  $\frac{1}{0.2} \ pounds$

Hence the lower limit of 120 pounds is

    $i = 120 - 0.1$

    $i = 119.9 \ pounds$

And  the upper  limit of 120 pounds is

    $l = 120 + 0.1$

    $l = 120.1 \ pounds$    

Generally given that the measuring weight on a scale that is accurate to the nearest 0.5 pound then  187 pounds will deviate by  $\frac{1}{0.5} \ pounds = 0.25 \ pounds$

Hence the lower limit of 120 pounds is

    $a = 187 - 0.25$

    $a = 186.75 \ pounds$

And  the upper  limit of 120 pounds is

    $b = 187 + 0.25$

    $b = 187.25 \ pounds$