Answer:
6
Step-by-step explanation:
First, we can expand the function to get its expanded form and to figure out what degree it is. For a polynomial function with one variable, the degree is the largest exponent value (once fully expanded/simplified) of the entire function that is connected to a variable. For example, x²+1 has a degree of 2, as 2 is the largest exponent value connected to a variable. Similarly, x³+2^5 has a degree of 2 as 5 is not an exponent value connected to a variable.
Expanding, we get
(x³-3x+1)² = (x³-3x+1)(x³-3x+1)
= x^6 - 3x^4 +x³ - 3x^4 +9x²-3x + x³-3x+1
= x^6 - 6x^4 + 2x³ +9x²-6x + 1
In this function, the largest exponential value connected to the variable, x, is 6. Therefore, this is to the 6th degree. The fundamental theorem of algebra states that a polynomial of degree n has n roots, and as this is of degree 6, this has 6 roots
Since
Is a perfect square, we can think of the "-6" at the end as a "+4-10" and we have
Which is the required form
F^-1(x)= x/9 + 1/3
To find this, just interchange the variables and solve for y.
y=9x-3
x=9y-3
x+3=9y
divide by nine
Answer:
m>7 = 142°
Step-by-step explanation:
m>6 = 38°
180° - 38° = 142°
m>7 = 142°
