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2 years ago

Please help me with this

Mathematics

1 answer:

lawyer [7]2 years ago

7 0

Answer:

14/18 =0.7778

Step-by-step explanation:

14/18 =0.7777.........=0.7778 rounded to the nearest thousandth

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I am pretty sure the answer is B

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2 years ago

Read 2 more answers

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mrs_skeptik [129]

Let's do

$\\ \rm\dashrightarrow y=\dfrac{3}{x-h}+k$

Release k for some while

we take h=0

y=3/x

So vertical asymptote is at origin now

It mentioned that it's at x=-5 so we need to change x

put -5 in place of h

$\\ \rm\dashrightarrow y=\dfrac{3}{x-(-5)}$

$\\ \rm\dashrightarrow y=\dfrac{3}{x+5}$

Vertical asymptote at x=-5

Now

for k=0 horizontal asymptote at origin

But it's given

y is at 12

Same put y=12 in place of k

$\\ \rm\dashrightarrow y=\dfrac{3}{x+5}+12$

h=-5
k=12

Graph attached for verification

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2 years ago

If a die is rolled 36 times, how many times is the number 4 expected to come up?

Snezhnost [94]

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3 years ago

The aspect ratio of a rectangular shape is it's length divided by it's width (L/W). If the aspect ratio of a chalkboard is 4:3 a

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2 years ago

Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin

ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let $\mu$ = mean duration of 15-sided union rugby games after the meeting.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 185 minutes {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, $H_A$ : $\mu$ < 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean duration of 15-sided union rugby games = 179 min

s = sample standard deviation = 12 minutes

n = sample of 15-sided rugby games = 36

So, the test statistics = $\frac{179-185}{\frac{12}{\sqrt{36} } }$ ~ $t_3_5$

= -3

The value of t test statistics is -3.

Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

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3 years ago