Question

PLEASE I NEED HELP!

Answer 1

Answer: $\frac{2ae^{3}}{3bd}$

Step-by-step explanation:

1. You have the following expression given in the problem above:

$\frac{2ab^{-1}}{3e^{-3}d}$

2. Then, according to the Negative exponent rule, you have that:

$a^{-n}=\frac{1}{a^{n}}$

3. So, based on the rule shown above, the negative exponents indicates that  $b$ must be in the denominator and  $e^{3}$ must be in the numerator. Therefore, you obtain the following expression:

  $\frac{2ae^{3}}{3bd}$