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lana66690 [7]
3 years ago
8

Cual es el complemento de 32 grados? :c

Mathematics
2 answers:
kiruha [24]3 years ago
3 0

Answer:

El complemento de 32 grados es 58 grados.

forsale [732]3 years ago
3 0
Do you still need help with this question?
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-25 Points-
ss7ja [257]

Answer:

1/36

Step-by-step explanation:

Each die has six sides, so there is always a 1/6 chance. The chances just continue to get slimmer as you go.

7 0
3 years ago
Read 2 more answers
Miguel biked 14 km in the same amount of time that linda hiked 10 km. Miguel's rate was 4 km/h more than linda's. How fast did e
matrenka [14]

The first thing we must do is define a variable.

We have then:

x: Linda's speed.

Then, by definition, the time traveled is equal to the distance between the velocity.

We have then:

For Linda:

t = \frac{10}{x}

For Miguel:

t = \frac{14}{x + 4}

Then, since time is the same, then:

\frac{10}{x} = \frac{14}{x + 4}

Clearing Linda's speed we have:

10 (x + 4) = 14x

10x + 40 = 14x

40 = 14x-10x

40 = 4x

x = \frac{40}{4}

x = 10

Then, Miguel's speed is:

x + 4 = 10 + 4 = 14

Answer:

Linda's speed is 10 Km/h

Miguel's speed is 14 Km/h

3 0
2 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s
Norma-Jean [14]

The positions when the particle reverses direction are:

s(t_1)=55ft\\\\s(t_2)=28ft

The acceleraton of the paticle when reverses direction is:

a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

s(t)=2t^{3}-21t^{2}+60t+3

So,

- Derivating to get the velocity function, we have:

v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42

Now, substituting the times to calculate the accelerations, we have:

a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}

Now, substitutitng the times to calculate the positions, we have:

s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft

Have a nice day!

3 0
3 years ago
If a fish swims 7/8 of the depth of a 32-foot deep lake, how many feet down did the fish swim?
Arlecino [84]
8/8 would be 32 so 7/8 would be 28 because 8 x 4 = 32 which would make each eight equal four. 
7 0
2 years ago
Read 2 more answers
PLEASE HELP I WILL MARK BRAINLIEST HAVE A GREAT DAY:)!!
faltersainse [42]

Answer:

F) 6/5

Step-by-step explanation:

6 divided by 5 = 6/5

7 0
3 years ago
Read 2 more answers
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