Ask question

Ask question

All categories

3 years ago

5

3x4²-(-6)²+4-6x4 Need help!! Please!!

1 answer:

goblinko [34]3 years ago

4 0

Assuming the x stands for multiplication... follow the ordering rules:

First let's take care of the exponents. 4²=16 and (-6)²=36. At the same time I will add some spacing between the terms:

3x16 - 36 + 4 - 6x4

Now do the multiplications:

48 - 36 + 4 - 24

The rest is just addition and subtraction

48 - 36 + 4 - 24 = -8

You might be interested in

List the constant(s) in the following expression:<br><br><br><br> 4c - r + 3

sukhopar [10]

The constant is 3.

In mathematics, a constant term is a term in an algebraic expression that has a value that is constant or cannot change, because it does not contain any modifiable variables.

5 0

3 years ago

Read 2 more answers

What are the solutions of the equation −2x−6=−2x−6 ?

Svet_ta [14]

Answer:

x = 0

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Xelga [282]

Amswer

it is b Step-by-step explanation:

8 0

3 years ago

The area of a rectangle is 42 ft squared, and the length of the rectangle is 5 ft more than twice the width. Find the dimensions

stira [4]

Answer:

<h3>Length = 12 ft</h3>

Width = $\frac{7}{2} ft$

Step-by-step explanation:

Given,

Area of rectangle = $42 \: {ft}^{2}$

Width = X

Length = 2x + 5

Now,

$x(2x + 5) = 42$

$2 {x}^{2} + 5x = 42$

$2 {x}^{2} + 5x - 42 = 0$

$2 {x}^{2} + 12x - 7x - 42 = 0$

$2x(x + 6) - 7(x + 6) = 0$

$(2x - 7)(x + 6) = 0$

Either

$2x - 7 = 0$

$2x = 0 + 7$

$2x = 7$

$x = \frac{7}{2}$

Or,

$x + 6 = 0$

$x = 0 - 6$

$x = - 6$

Negative value can't be taken.

So, width = $\frac{7}{2} ft$

Again,

Finding the value of length,

Length = $2x + 5$

$2 \times \frac{7}{2} + 5$

$7 + 5$

$12$

Length = 12 ft

7 0

3 years ago

Read 2 more answers

Solve |3x + 3|= 27

Alenkasestr [34]

Answer:

d.x=-8 and x=-10

Step-by-step explanation:

4 0

3 years ago