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dalvyx [7]
4 years ago
6

How many weeks is 18 days?

Mathematics
2 answers:
MrRissso [65]4 years ago
8 0

Answer:

Step-by-step explanation:

18/7=2.57

vaieri [72.5K]4 years ago
4 0

Answer:

ok so we know there are 7 days per week.

so now we are looking to see how many times 7 days (a week) can fit in 18

Step-by-step explanation:

18/7=2.6

so 2 weeks,

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Elena is buying cups and plates for her party. Cups are sold in packs of 8 and plates are sold in packs of 6. She wants to have
AnnZ [28]

Answer:

24 and 48

Step-by-step explanation:

If she had 24 of each, she would have 3 packs of cups, and 4 packs of plates.

If she had 48 of each, she would have 6 packs of cups, and 8 packs of plates.

6 0
3 years ago
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David put $1500 in a savings account that earns 4% simple interest for 6 months. How
Mazyrski [523]

Answer:

<h2>$1560</h2>

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1500 + (1500 : 100 × 4)

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3 0
3 years ago
What is 10% off £1.80?
frosja888 [35]
To find 10% you divide the amount by 10 so £1.80 dived by 10 is 0.18p. Therefore you want 10% OFF that amount so you do £1.80-0.80p and you are left with £1.00.
4 0
3 years ago
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6) Salem Sue is a giant cow statue in North Dakota. The cow is 38 feet high. A real
exis [7]

The size of chicken at the form would be 111.8 inches.

Step-by-step explanation:

Given that,

The average height of cow = x1 = 4 feet 5 inches

x1 = 4 x 12 + 5 = 53 inches   (12 inches in a feet)

The average height of chicken = y1 = 13 inches.

The height of cow statue at form = x2 = 38 feet

x2 = 38 x 12 = 456 inches

The height of chicken statue = y2 = ?

For this, the ratio of height in both the scenarios would be the same. Therefore,  

x1/y1 = x2/y2

now, by putting the values

53/13 = 456/y2

y2 = (456x 13) / 53

y2 = 111.8 inches

Hence, the size of chicken at the form would be 111.8 inches.

6 0
4 years ago
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If c is the hypotenuse of a right triangle,find the missing side. If necessary, round to the nearest hundredth. c=sqrt(155), b=s
Lunna [17]
A^2 + 31 = 155  - I squared each of b and c for those numbers
a^2 = 155 - 31
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6 0
4 years ago
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