The value of .
Solution:
Given equations:
7x + 2y = 57 ---------- (1)
x + 2y = 5 ---------- (2)
Subtract 2y from both sides of the equation (2).
x = 5 – 2y ---------- (3)
Substitute equation (3) in equation (1).
7(5 – 2y) + 2y = 57
35 – 14y + 2y = 57
35 – 12y = 57
Subtract 35 from both sides of the equation.
–12y = 22
Divide by 12 on both sides.
Substitute y value in equation (3).
Hence the value of .
Answer:
There are no real values of x for point P to belong to the 4 quadrant
Step-by-step explanation:
<u><em>The question in English is</em></u>
To what real values of x does the point P (3x -6, 2x +4) belong to the 4th quadrant?
we know that
A point in the fourth Quadrant has the x-coordinate positive and the y-coordinate negative
we have the point
P (3x-6, 2x+4)
----> inequality A ( x-coordinate must be positive)
---> inequality B ( y-coordinate must be negative)
Solve Inequality A
-----> (2,∞)
Solve Inequality B
----> (-∞,-2)
The solution of the system is
(-∞,-2) ∩ (2,∞)
therefore
The system has no solution
There are no real values of x for point P to belong to the 4 quadrant
