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Trava [24]
4 years ago
6

Write a quadratic equation in standard form that has two solutions, -5 and 7

Mathematics
1 answer:
nadya68 [22]4 years ago
4 0

Answer:

{b}^{2}  -  {2b}  - 35

Step-by-step explanation:

1) find two factors of c that sum up to -2.

2) 5 and -7 are factors of -35 that sum up to -2.

3) (x+5)(x-7)

4) x+5= 0, x= -5

5) x-7= 0, x= 7

4) the two solutions are -5 and 7.

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Solve. 3(a – 5) – 6 = –15
Andre45 [30]

Answer:

a=6

Step-by-step explanation:

distribute:

3a-15-6=-15

combine like terms:

3a-21=-15

add 21 to each side:

3a=6

divide by 3:

a=2

5 0
2 years ago
The number w and 0.8 are additive inverses.
umka2103 [35]

Since, the number w and 0.8 are additive inverses.

A number 'a' is said to have an additive inverse '-a' if "a+ (-a)= 0".

Since, 'w' and '0.8' are additive inverses of each other such that w + 0.8 = 0

Therefore, the value of 'w' should be '-0.8' so that -0.8 + 0.8 = 0.

So, the value of 'w' is =0.8

Now, Refer to the attached image which represents the position of 0.8 , w ( that is -0.8) and the sum of 0.8 and w.

Sum of 0.8 and w = 0.8 + w

= 0.8 +(-0.8)

= 0.

3 0
3 years ago
Read 2 more answers
The temperature dropped 12F in 8 hours .if the final temperature was -7,what was the starting temperature
bekas [8.4K]
Just add 12 to -7, -7 -6 -5 -4 -3 -2 -1 0 1  2  3  4  5  6  7  8  9  10  11  12
6 0
3 years ago
Kristen bought a 14 ounce bottle of catshup for 91 cents. At the same rate, how much would a 20-ounce bottle cost?
strojnjashka [21]

Answer:

$1.30 or 130 cents

Step-by-step explanation:

You divide 91 by 14 to get the amount per ounce and you would get 6.5. Then you multiply that by 20 to get the new amount which is 130, or $1.30.

4 0
3 years ago
Una empresa exportadora de frutas vende dos variedades de frambuesas: estándar y de lujo. Una caja de freses estándar se vende e
aksik [14]

Answer:

83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.

Step-by-step explanation:

Representemos el número de cajas como

A = caja estándar de frambuesas

B = caja de lujo de frambuesas

Caja estándar de frambuesas = $ 7 Caja de lujo de frambuesas = 10.

A + B = 135 ......... Ecuación 1

B = 135 - A

7A + 10B = 1100 ........... Ecuación 2

Sustituir

135 - A para B en la ecuación 2

7A + 10 (135 - A) = 1100

7A + 1350 -10A = 1100

7A - 10A = 1100-1350

-3A = - 250

A = 250/3

A = 83.33 cajas

Sustituye 83.33 por A en la ecuación 1

A + B = 135

83,33 + B = 135

B = 135 - 83.33 = 51.67 cajas

Por lo tanto, vendió,

83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.

6 0
3 years ago
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