Answer:
k = 1 + sqrt(7/2) or k = 1 - sqrt(7/2)
Step-by-step explanation:
Solve for k over the real numbers:
4 k - 10/k = 8
Bring 4 k - 10/k together using the common denominator k:
(2 (2 k^2 - 5))/k = 8
Multiply both sides by k:
2 (2 k^2 - 5) = 8 k
Expand out terms of the left hand side:
4 k^2 - 10 = 8 k
Subtract 8 k from both sides:
4 k^2 - 8 k - 10 = 0
Divide both sides by 4:
k^2 - 2 k - 5/2 = 0
Add 5/2 to both sides:
k^2 - 2 k = 5/2
Add 1 to both sides:
k^2 - 2 k + 1 = 7/2
Write the left hand side as a square:
(k - 1)^2 = 7/2
Take the square root of both sides:
k - 1 = sqrt(7/2) or k - 1 = -sqrt(7/2)
Add 1 to both sides:
k = 1 + sqrt(7/2) or k - 1 = -sqrt(7/2)
Add 1 to both sides:
Answer: k = 1 + sqrt(7/2) or k = 1 - sqrt(7/2)
Step-by-step explanation:
we know that
Work =f*d
=25*100
=2500Joule
therefore work done is 2500Joule
Answer:
B
Step-by-step explanation:
lets say the cost for a pound is 2$
if the watermelon weighs 3 pounds it would cost $6.
2(3)
The weight is the variable in the parenthesis because that is what is constantly changing.
Well you haven't really given us a question that requires a "quantifiable" answer. 2 ounces is roughly equivalent to 60 grams. 2 ounces of ketchup wouldn't be an awful lot of ketchup. I'm sure that you'd remain healthy despite eating 2 ounces of ketchup along with your potato wedges.
According to the American Heart Association, women should only have about 25 grams of sugar per day. In 100g of ketchup there would be about 22g grams of sugar. If you were to eat roughly 60g of ketchup, you'd only be digesting about 13.2 grams of sugar. Now, potato wedges could also contain sugar, but you haven't stated how many grams or kilograms of potato wedges you'd be eating, so I wouldn't be able to tell you whether your meal contains too much sugar.
19030.95
i think
take the og number times the percent then that times three and add it to the original number (sorry if that’s not right that’s just how i would do it)
