Answer:
<u>Width = 7 inches</u>
<u>Length = 23 inches</u>
Step-by-step explanation:
Let :
Equating to area :
- (2x + 9)(x) = 161
- 2x² + 9x = 161
- 2x² + 9x - 161 = 0
- 2x² - 14x + 23x - 161 = 0
- 2x(x - 7) + 23(x - 7) = 0
- x - 7 = 0
- x = 7
Dimensions are :
- <u>Width = 7 inches</u>
- Length = 2(7) + 9
- <u>Length = 23 inches</u>
Yo sup??
We can solve this problem by applying trigonometric ratios.
sin36=XY/WY
WY=5/sin36
=8.5
Hope this helps.
Answer:
<h2>Cubing both sides of an equation is reversible.</h2>
Step-by-step explanation:
Squaring both sides of an equation is irreversible, because the square power of negative number gives a positive result, but you can't have a negative base with a positive number, given that the square root of a negative number doesn't exist for real numbers.
In case of cubic powers, this action is reversible, because the cubic root of a negative number is also a negative number. For example
![\sqrt[3]{x} =-1](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3D-1)
We cube both sides
![(\sqrt[3]{x} )^{3} =(-1)^{3} \\x=-1](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bx%7D%20%29%5E%7B3%7D%20%3D%28-1%29%5E%7B3%7D%20%5C%5Cx%3D-1)
If we want to reverse the equation to the beginning, we can do it, using a cubic root on each side
![\sqrt[3]{x}=\sqrt[3]{-1} \\\sqrt[3]{x}=-1](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3D%5Csqrt%5B3%5D%7B-1%7D%20%5C%5C%5Csqrt%5B3%5D%7Bx%7D%3D-1)
There you have it, cubing both sides of an equation is reversible.
Answer and explanation:
25 x 3 = 75
75 x 2 = 150
I found the product of the first two numbers, then multiplied the third.
The answer is 150. Hope this helps!
Answer:
9
Step-by-step explanation:
2^28(3^-2/2^3)^4 x 1/(3^-5 x 2^8 x 6^0)^2
2^28(3^-2/2^3)^4 x 1/(3^-5 x 2^8 x 1)^2
2^28(3^-2/2^3)^4 x 243^2/256^2
2^28 x 1/2^12 x 3^8 x 243^2/256^2
243^2 x 1 x 2^28/256^2 x 3^8 x 2^12
2^28 x 243^2/2^12 x 3^8 x 256^2
2^16 x 243^2/3^8 x 256^2
2^16 x 3^10/2^16 x 3^8
=3^2
=9