A company manufactures 2,000 units of its flagship product in a day. The quality control department takes a random sample of 40
2 answers:
Answer:
Option b is the correct answer.
b) 100 pieces must be defective.
Step-by-step explanation:
The table shows the data of the number of days the 40 units of item would last,
39 31 38 40 29
32 33 39 35 32
32 27 30 31 27
30 29 34 36 25
30 32 38 35 40
29 32 31 26 26
32 26 30 40 32
39 37 25 29 34
Also, If the product has a lifespan of less than 26 days, it is considered defective.
So, the number of items which are defective out of 40 items are: 2
Hence, the proportion of items that are defective out of 40 items are:
2/40=1/20
Hence, the number of defective items out of 2000 items are:
Hence, number of defective items out of 2000 are: 100
Hence, option a), c) and e) are incorrect.
Also, the population proportion of defective items is:
1/20
and sample proportion is:
40/2000=1/50
as both are not equal.
Hence option d) is incorrect.
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Using the z-distribution, it is found that since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.
<h3>What are the hypothesis tested?</h3>At the null hypothesis, it is tested if there is not enough evidence that the proportion is below 85%, that is:
At the alternative hypothesis, it is tested if there is enough evidence that the proportion is below 85%, that is:
The test statistic is given by:
In which:
is the sample proportion.
- p is the proportion tested at the null hypothesis.
- n is the sample size.
For this problem, the parameters are:
Hence the test statistic is:
z = -1.68
<h3>What is the p-value and the conclusion</h3>Using a z-distribution calculator, with a left-tailed test, as we are testing if the proportion is less than a value, and z = -1.68, the p-value is of 0.0465.
Since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.
More can be learned about the z-distribution at brainly.com/question/16313918
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Answer:
Therefore 80 ceperies will he need to sell this month.
Step-by-step explanation:
Average: Average is the ratio of sum of all numbers to the total number present in the data.
Given that Herbert has sold 99, 37, 86 and 73 copeirs in the last 4 months.
Let he need to sell x copeirs in this month.
According to the problem,
⇒ 99+37+86+73+x= 75×5
⇒295 + x= 375
⇒x = 375 - 295
⇒ x= 80
Therefore 80 ceperies will he need to sell this month.