.4 is smallest, 1/2 , then 60% is greatest.
Big marbles = 45red 3/4 blue
Small marbles = 2/5 red 3/5 blue 24 more small blue mabrles than red marbles
What percentage of the marbles are big marbles
First of all lets working out the missing values:
Big Marbles, 45 red, 3/4 blue. If 45 red is 1/4, then 135 (45*3) is 3/4.
Big Marbles, 45 red, 135 blue = 180 in total
For the small marbles, we do some logical thinking:
If red is 2/5, and blue is 3/5. And blue has 24 more than red.
That means 24 = 1/5
So in total there are 120 small marbles (24*5)
There are 180 big marbles
We add these together, 120 + 180 = 300 marbles
180 / 300 = 0.6 = 60%
^ Divide the big marbles by the number of total marbles
60% of the marbles are big marbles
<u>Please vote my answer brainliest if I helped!</u>
343^1/3
=(7)^3*1/3 [ 3 and 3 are cancelled]
=7
Since .7 is above 5.
$45.71 would turn to $46.00.
You would round 45... the 5 to 6...
To be $46
For the first 60 positive integers, a = 1, n = 60, l = 60.
Sn = n/2(a + l)
s = 60/2(1 + 60) = 30(61)
For the next 60 positive integer, a = 61, n = 60, l = 120
Sum = 60/2(61 + 120) = 30(61 + 120) = 30(61) + 30(120) = s + 3600
Sum of first 120 positive integers = s + s + 3600 = 2s + 3600
