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Lady bird [3.3K]
3 years ago
5

s. Blake spent 11 hours making gift baskets for families. Each gift basket took 1/5 hours to make. How many gift baskets did Ms.

Blake make in 11 hours?
Mathematics
1 answer:
Iteru [2.4K]3 years ago
3 0

Answer:

55

Step-by-step explanation:

If 1 gift takes 1/5 an hour, then 5 gifts would take one hour. So if she makes 5 gifts an hour for 11 hours she would make 55 gifts in 11 hours.

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The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers.
LiRa [457]
n=\dfrac{1}{2}(n+1)+10\\
2n=n+1+20\\
n=21\\
n+1=22

21 and 22
7 0
3 years ago
A bag contains 8 milk and 9 dark chocolates.
Triss [41]

Answer

P(milk)= 8/17

P(not milk)=9/17

Because 8+9=17

hope this was helpful!!!!

4 0
3 years ago
Please help me!!!!!!
LiRa [457]

Answer:

y=-(3/4)x-3

Step-by-step explanation:

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6 0
3 years ago
Need help #3. The answer is shown, but I don’t know how to get to the answer. Please teach and show steps.
Sunny_sXe [5.5K]

Answer:

A

Step-by-step explanation:

We are given a right triangle with a base of <em>x</em> feet and a height of <em>h</em> feet, where <em>x</em> is constant and <em>h</em> changes with respect to time <em>t</em>.

The angle in radians is defined by:

\displaystyle \tan(\theta)=\frac{h}{x}

And we want to find the relationship that describes dθ/dt and dh/dt.

So, we will differentiate both sides with respect to <em>t</em> where <em>x</em> is a constant:

\displaystyle \frac{d}{dt}[\tan(\theta)]=\frac{d}{dt}\Big[\frac{h}{x}\Big]

Differentiate. Apply the chain rule on the left. Again, remember that <em>x</em> is just a constant, so we can move it outside the derivative operator. Therefore:

\displaystyle \sec^2(\theta)\frac{d\theta}{dt}=\frac{1}{x}\frac{dh}{dt}

Since we know that tan(θ)=h/x, <em>h</em> is the opposite side of our triangle and <em>x</em> is the adjacent. Therefore, by the Pythagorean Theorem, our hypotenuse will be:

\text{Hypotenuse}=\sqrt{h^2+x^2}

Since secant is the ratio of the hypotenuse to adjacent:

\displaystyle \sec(\theta)=\frac{\sqrt{h^2+x^2}}{x}

So:

\displaystyle \sec^2(\theta)=\frac{x^2+h^2}{x^2}

By substitution, we have:

\displaystyle \Big(\frac{x^2+h^2}{x^2}\Big)\frac{d\theta}{dt}=\frac{1}{x}\frac{dh}{dt}

By multiplying both sides by the reciprocal of the term on the left:

\displaystyle \frac{d\theta}{dt}=\frac{1}{x}\Big(\frac{x^2}{x^2+h^2}\Big)\frac{dh}{dt}

Therefore:

\displaystyle \frac{d\theta}{dt}=\frac{x}{x^2+h^2}\frac{dh}{dt}

Our answer is A.

3 0
3 years ago
.2.15
Debora [2.8K]
The answer is A because there is a common difference of 3 and that makes it Arithmetric
8 0
3 years ago
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